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3 years ago

Please help me it’s due today and i don’t understand, i’ll give brainliest.

Mathematics

1 answer:

IgorC [24]3 years ago

7 0

AC= √CD^2+AD^2
AC= √AB^2+BC^2
Those two are true
See explanation in photo below
Good luck

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Evaluate n/6 plus 2 when n=2

harina [27]

Step-by-step explanation:

n/6+2=0

n/6+2/1=0

find the LCM=6

n+12/6=0

cross multiply

n+12=0

n=-12

5 0

3 years ago

A map is laid out in the standard (x,y) coordinate plane. How long, in units, is an airplane's path on the map as the airplane f

xeze [42]

Answer:

Distance between the points A and B is 15.52 units.

Step-by-step explanation:

It has been given in the question that an airplane flies along a straight line from City A to City B.

Map has been laid out in the (x, y) coordinate plane and the coordinates of these cities are A(20, 14) and B(5, 10).

Distance between two points A'(x, y) and B'(x', y') is represented by the formula,

d = $\sqrt{(x-x')^{2}+(y-y')^{2}}$

So we plug in the values of (x, y) and (x', y') in the formula,

d = $\sqrt{(20-5)^{2}+(14-10)^{2}}$

d = $\sqrt{(15)^{2}+(4)^{2}}$

d = $\sqrt{225+16}$

d = 15.52

Therefore, distance between the points A and B is 15.52 units.

4 0

3 years ago

Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)

Sloan [31]

The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...

the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. 
2cosθ = 1 => θ = ±π/3 

A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ 
= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ 
= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. 
.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] 
= 3θ/2 +sin(2θ) - sin(θ) 

Area = A(π/3) - A(-π/3) 
= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) 
= π.

7 0

4 years ago

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

Yuki888 [10]

$d=v \cdot t$
d - distance
v - speed
t - time

Car A:
$v_1 \\
t_1=2 \\
d_1=v \cdot 2=2 v$

Car B:
15 mph faster than car A
$v_2=v_1+15 \\ t_2=1.5 \\ d_2= (v_1+15) \cdot 1.5=1.5v_1 + 22.5$

Both cars traveled equal distances:
$d_1=d_2 \\
2v_1 = 1.5v_1+22.5 \\
2v_1-1.5v_1=22.5 \\
0.5v_1=22.5 \\
v_1=45 \\ v_2=45 + 15 =60$

Car B traveled at the speed of 60 mph.

6 0

3 years ago

Can someone help please (highlighted in blue)

Annette [7]

$\implies {\blue {\boxed {\boxed {\purple {\sf {B)\:10}}}}}}$