Please help me it’s due today and i don’t understand, i’ll give brainliest.

Mathematics

1 answer:

IgorC [24]3 years ago

7 0

AC= √CD^2+AD^2
AC= √AB^2+BC^2
Those two are true
See explanation in photo below
Good luck

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Hi! I've tried this problem a couple times but am still stumped :( Can you help?!

aniked [119]

ANSWER:

$X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

EXPLANATION:

Given:

$U\text{ = }\begin{bmatrix}{1} & {3} & {-5} \\ {2} & {14} & {11} \\ {-8} & {0} & {5}\end{bmatrix}\text{ V =}\begin{bmatrix}{13} & {1} & {-7} \\ {-6} & {1} & {9} \\ {0} & {15} & {23}\end{bmatrix}$

Since U and V are Matrices with equal dimensions(3 x 3 matrix), and

X + U = V.

To solve for X, we have:

X = V - U

$\begin{gathered} X\text{ = V - U} \\ X\text{ = }\begin{bmatrix}{13-1} & {-1-3} & {-7-(-5)} \\ {-6-2} & {1-14} & {19-11} \\ {0-(-8)} & {15-0} & {23-5}\end{bmatrix}=\text{ }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix} \end{gathered}$ $X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}$

6 0

1 year ago

Please help and show work!!

Sergio [31]

A(-2, 2), B(4, 2), C(-6, -1), D(0, -1)

AB = CD = 4 - (-2) = 4 + 2 = 6

BD = AC. Use the formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$