The slope of the line of the equation given is -2 (by solving for y, you get y = -2x+4).
So, in order to be perpendicular, you must take the negative reciprocal.
The slope would be -1/2.
they have the same amount of sides as they do angles,
Answer:
The height of the flagpole is 46 feet
Step-by-step explanation:
First we find the ratio to connect the variables
Tan(∅) = opposite/adjacent
Plug in the Variables
Tan(39) = x/50
Solve for x
50*tan(39) = x
x = 40.48
Don't forget to include the man's height
40.48 + 6 = 46.48
2.0x10^-5 or 2.0E-5 —this is because as a small decimal number, you move the decimal to the right five spaces and then add a negative to the decimal to indicate that when you translate back (from scientific notation to 0.00002) you will move the decimal to the left
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
