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Viefleur [7K]
3 years ago
12

What is the area of the triangle above?

Mathematics
1 answer:
Alex73 [517]3 years ago
5 0

Answer:

look at the picture i have sent

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Express the following as:<br>ax+by+c=0<br><br>-2x+3y=6​
Cerrena [4.2K]

The expression -22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

<h3>Linear Equations</h3>

The given equation is:

-2x + 3y = 6

Comparing the equation above with ax + by + c = 0

Rewrite -2x + 3y = 6 in the form ax + by + c = 0

-2x + 3y - 6 = 0

If -2x + 3y - 6 = 0 is compared with ax + by + c = 0

a = -2, b = 3, c = -6

Therefore, the expression-22x + 3y = 6 in the form ax + by + c = 0 is -2x + 3y - 6 = 0

Learn more on linear equations here: brainly.com/question/14323743

8 0
2 years ago
Read 2 more answers
A company design a logo using a kite figure around the letter t
aliina [53]
The answer is 192sq.cm.
REASONING: This would be by multiply the length by the height in order to get the area. 12*19 is equal to 192.
PLEASE MARK BRAINIEST!! Have a good day!
6 0
3 years ago
The perimeter of a rectangle is 96cm its shortest side has a length of 5cm state the length of the longest side​
Rainbow [258]

Answer:

43cm

Step-by-step explanation:

96-10 (5 x2 sides)=86

86/2 sides=43 longest side

4 0
3 years ago
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 &lt; m &lt; 13 &lt; n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

4 0
3 years ago
How do you complete a graph based on a table
EastWind [94]

by calculating the given information and the equation in table

7 0
3 years ago
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