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harkovskaia [24]
4 years ago
11

Help me please, thanks again if you do :)

Mathematics
2 answers:
taurus [48]4 years ago
8 0

Answer: B) 6

Step-by-step explanation:

First let's distribute the left side of the equation.

k - 16 + 4k = -2(2k -1) + 6k

Then let's combine like terms on the left side of the equation.

5k - 16 = -2(2k - 1) + 6k

Then let's distribute the right side of the equation.

5k - 16 = -4k + 2 + 6k

Then let's combine like terms on the right side of the equation.

5k - 16 = 2k + 2

Then let's move all the x's to one side, and all the constants to the other.

3k = 18

Then divide both sides of the equation by 3.

k = 6

Hope it helps <3

antiseptic1488 [7]4 years ago
5 0

Answer:

6

Step-by-step explanation:

k - 16 + 4k = -2(2k -1) + 6k

5k - 16 = -2(2k - 1) + 6k

5k - 16 = -4k + 2 + 6k

5k - 16 = 2k + 2

3k = 18

k = 6

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Answer:

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

Step-by-step explanation:

Total plants = 11

Domestic plants = 7

Outside the US plants = 4

Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:

P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ

where n = total no. of trials

           x = no. of successful trials

           p = probability of success

           q = probability of failure

Here we have n=4, p=4/11 and q=7/11

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰

          = 1 - 0.16399

P(X≥1) = 0.836

The probability that a performance evaluation will include at least one plant outside the United States is 0.836.

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