Select a transition metal? A.Fe B.Al C.Li D.N

Can you plz help me thank you dont be mean

Anton [14]

the fact that u would post ur whole test on here i see if u posting 3 but the whole test Girllllllllll

6 0

4 years ago

N2+3H2=>>2NH3. If 6.72dm³ of each of Nitrogen and hydrogen (measured at S.T.P.) are made to produced Ammonium. Which of th

torisob [31]

Answer:

Hydrogen, 0,2 mol

Explanation:

$V_{M}$ = 22, 4 l/mol

V ( $N_{2}$ ) = 6,72 $dm^{2}$ = 6,72 l

V ( $H_{2}$ ) = 6,72 $dm^{2}$ = 6,72 l

The formula is:

n = $\frac{V}{V_{M} }$

n ( $N_{2}$ ) = 6,72l /22,4 l/mol = 0,3 mol

n ( $H_{2}$ ) = 6,72l /22,4 l/mol = 0,3 mol (the same)

But from the equation we get a proportion that 1 mol ( $N_{2}$ ) - 3 mol ( $H_{2}$ )

$\frac{0,3}{1} > \frac{0,3}{3}$ (we have more hydrogen than is need for the reaction)

So there is excess of $H_{2}$

We only need $\frac{0,3}{3}$ = 0,1 mol ( $H_{2}$ )

0,3 mol (hydrogen quantity we have) - 0,1 mol (hydrogen quantity we need for the reaction) = 0,2 mol (excess)

make me the brainliest

3 0

3 years ago

If you had a 0.200 L solution containing 0.0140 M of Fe3+(aq), and you wished to add enough 1.27 M NaOH(aq) to precipitate all o

Lelechka [254]

Answer: 6.6 ml

Explanation:

If you had a 0.200 L solution containing 0.0140 M of Fe3+(aq), and you wished to add enough 1.27 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH−(aq) for the precipitation.

You have 0.014X0,2 = 0,0028 moles of Fe ion.

You need 0,0028 X 3 = 00084 moles of OH

The NaOH is 1.27 moles/liter

0.084/1.27 = 6.6 ml

8 0

3 years ago

What must be true when work is done?

klio [65]

In order to accomplish work on an object there must be a force exerted on the object and it must move in the direction of the force. ... For the special case of a constant force, the work may be calculated by multiplying the distance times the component of force which acts in the direction of motion.

7 0

3 years ago

Determine the mass of hydrogen gas collected in a container if the gas occupies 44.8 L at STP.

aleksandrvk [35]

Answer:

Hope this helps kinda got confused mid way

Explanation:

So the hydrogen sulphide is H2S for the molecular formula. Then the mass of hydrogen sulphide would be 1×2+32= 34g/mol At STP.

6 0

3 years ago

Select a transition metal?A.FeB.AlC.LiD.N​

Select a transition metal?A.FeB.AlC.LiD.N