Answer:
a) The probability that at least 5 ties are too tight is P=0.0432.
b) The probability that at most 12 ties are too tight is P=1.
Step-by-step explanation:
In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.
a) We can express the probability that at least 5 ties are too tight as:
The probability that at least 5 ties are too tight is P=0.0432.
a) We can express the probability that at most 12 ties are too tight as:
The probability that at most 12 ties are too tight is P=1.
Answer:
A.
This assumption is that the distribution of polyunsaturated fat % of each if these four regimes must be with equal variances as well as uniform.
B.
The null hypothesis
H0: μ1 = μ2 = μ3 = μ4
The alternate hypothesis:
H1: at least 2 means are unequal
C.
First we calculate the grand mean
= 1/54[15(42.9)+17(43.1)+8(43.7)+14(43.9)]
= (643.5 +732.7 + 349.6 + 614.6)/54
= 2340.4/54
= 43.341
Sum of squared treatment
= [15(42.9-43.341)²+17(43.1-43.341)²+8(43.7-43.341)²+14(43.9-43.341)²]
= 9.3104
Mean square of treatment
= SST/I-1
= 9.3104/4-1
= 9.3104/3
= 3.1035
Error sum of squared
= (15-1)*(1.3)² + (17-1)*(1.5)² + (8-1)*(1.2)² + (14-1)*(1.2)²
= 88.46
Error mean square
MSE = 88.46/54-4
= 1.7692
Test statistic
= 3.1035/1.7692
= 1.75
What I would do is convert the fractions to decimals (just personal preference) making the trombone 8.93 feet and the french horn 17.21 feet. The tuba would be 0.79 feet longer than the french horn, and the french horn would be 8.23 feet longer than the trombone. However, if you need the answer to remain a fraction, the tuba would be 11/14 feet longer than a french horn, and a french horn would be 8 3/14 feet longer than a trombone.
The equation here is 1 1/4 X 6
1X6= 6 and 1/4 X6 = 6/4
You can add these to and the answer is 6 6/4
which can then be simplified to 7 1/2 hours in 6 days
Answer:
Step-by-step explanation:There are other kinds of numbers that can be graphed on the number line, too. ... which are natural numbers and which are whole numbers is to think of a “hole,” which can be represented by 0. ... Notice that distance is always positive or 0.
