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3 years ago

6

PLEASE HELP ME!!!!!!!Which expression is equivalent to 6x2−(4x+10)−3+(4x2−5x)?

1 answer:

bixtya [17]3 years ago

7 0

Answer:

10(-4x+10)-3 +(8-5x)

-40x+100-3+8-5x

-40x-5x+105

-45x+105

-45x+105=0

-45x=-105

x=-105/-45

x=7/3

Step-by-step explanation:

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Answer:

a) The total weight of fruits is $8\,\frac{1}{4}$ kilograms, b) The weight of the fruits left is $4\,\frac{1}{2}$ kilograms.

Step-by-step explanation:

a) The total weight of fruits ( $m_{T}$ ) is calculated by the following formula:

$m_{T} = m_{a} + m_{m}+m_{o}$

Where:

$m_{a}$ - Total weight of apples, measured in kilograms.

$m_{m}$ - Total weight of mangoes, measured in kilograms.

$m_{o}$ - Total weight of oranges, measured in kilograms.

If $m_{a} = 1\,\frac{1}{2} \,kg$ , $m_{m} = 5\,\frac{1}{4}\,kg$ and $m_{o} = 1\,\frac{1}{2}\,kg$ , then:

$m_{T} = 1\,\frac{1}{2}\,kg + 5\,\frac{1}{4}\,kg + 1\,\frac{1}{2}\,kg$

$m_{T} = \frac{6}{4}\,kg + \frac{21}{4}\,kg + \frac{6}{4}\,kg$

$m_{T} = \frac{33}{4}\,kg$

$m_{T} = 8\,\frac{1}{4}\,kg$

The total weight of fruits is $8\,\frac{1}{4}$ kilograms.

b) The weight eaten by her family is determined by the following expression:

$m_{E} = m_{a,e} + m_{m,e} + m_{o,e}$

Where:

$m_{a,e}$ - Eaten weight of apples, measured in kilograms.

$m_{m,e}$ - Eaten weight of mangoes, measured in kilograms.

$m_{o,e}$ - Eaten weight of oranges, measured in kilograms.

Given that $m_{a,e} = \frac{3}{4}\,kg$ , $m_{m,e} = 2\,\frac{1}{2}\,kg$ and $m_{o,e} = \frac{1}{2}\,kg$ , the weight eaten by her family is:

$m_{E} = \frac{3}{4}\,kg + 2\,\frac{1}{2}\,kg + \frac{1}{2}\,kg$

$m_{E} = \frac{3}{4}\,kg + \frac{10}{4}\,kg + \frac{2}{4}\,kg$

$m_{E} = \frac{15}{4}\,kg$

$m_{E} = 3\,\frac{3}{4}\,kg$

The weight of the fruits left is found by subtraction:

$m_{R} = m_{T}-m_{E}$

$m_{R} = 8\,\frac{1}{4} \,kg -3\,\frac{3}{4}\,kg$

$m_{R} = \frac{33}{4}\,kg-\frac{15}{4}\,kg$

$m_{R} = \frac{18}{4}\,kg$

$m_{R} = 4 \,\frac{1}{2}\,kg$

The weight of the fruits left is $4\,\frac{1}{2}$ kilograms.

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