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3 years ago

6

There is a photograph of a painting measures 13 unites by 17 units. If the scale factor is 1/3, what is the actual size of the p

ainting?
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1 answer:

MrRissso [65]3 years ago

8 0

Answer 39 units by 51 units
Hope this helps

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The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle

AVprozaik [17]

Answer:

Length of rectangle is 31 yards and Width is 24 yards.

Given:

The length of a rectangle is 7 more than the width.
The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

$\\ \: \: \: \: \pink{ \dashrightarrow \: \: \: \: \sf { \underbrace{Area_{(Rectangle)} = Length × Width }}} \\ \\$

On Substituting the required values, we get;

$\\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x = 24 \: or \: - 31 \\ \\$

As we know that width of the rectangle can't be negative. So x = 24

<u>Hence</u>,

Width of rectangle = x = 24 yards
Length of the rectangle = x + 7 = 31 yards

$\therefore$ Length of rectangle is 31 yards<u> </u>and Width is 24 yards.

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