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lisov135 [29]
3 years ago
13

ILIO

Mathematics
1 answer:
galben [10]3 years ago
8 0
It should be choice c
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Find the solutions of the quadratic equation - 2^2+ 3x – 3 = 0
Assoli18 [71]

Answer:

-1/3

Step-by-step explanation:

2^2 + 3x - 3 = 0

4 - 3 + 3x = 0

1 + 3x = 0

x = -1/3

Hope it helps

7 0
2 years ago
The coordinates of points M,N, and P are ....
Rainbow [258]

Answer:

(-1, -1) Let me know if the explanation didn't make sense.  

Step-by-step explanation:

If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left.  This means M is only connected to N here and P is only connected to N.  So we want to find the slope of these two lines.

MN is easy since their y values are the same, the slope is 0.

NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.

So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0.  To find these lines  weuse point slope form  for those two points.  The formula for point slope form is y - y1 = m(x-x1)

y-3 = -4(x+2) -> y = -4x-5

y+1 = 0(x-5) -> y = -1

So now we want these two to intersect.  We just set them equal to each other.

-1 = -4x -5 -> -1 = x

So this gives us our x value.  Now we can plug that into either function to find the y value.  This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)

8 0
3 years ago
Help with this problem?
ankoles [38]
3(x-8)=12
I got this equation since there are three of the "x-8" sections that add up to the twelve length bar above
5 0
3 years ago
If f(x)=5x, what is f^-1(x)?
Georgia [21]

Answer:

first thing to do is get up from your sit and go cry because that question is to hard

5 0
3 years ago
How do I find the distance between (-2,5) and (22,12)
jok3333 [9.3K]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{22}~,~\stackrel{y_2}{12})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[22-(-2)]^2+[12-5]^2}\implies d=\sqrt{(22+2)^2+(12-5)^2} \\\\\\ d=\sqrt{24^2+7^2}\implies d=\sqrt{625}\implies d=25

6 0
3 years ago
Read 2 more answers
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