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malfutka [58]
2 years ago
9

HELP RIGHT AWAY!!!PLEASE EXPLAIN HOW TO SOLVE THE PROBLEM

Mathematics
1 answer:
kumpel [21]2 years ago
8 0

Answer:

264

Step-by-step explanation:

Volume = Area of cross section x height

Area of cross section = 1/2 bh

1/2 (8x6) = 24

24 x 11 = 264 yd^3

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Question 3: Solve the Variables<br> Will give brainliest, must show work and answers!
dybincka [34]
3.

x = 3   because the 2 legs of 45-45-90 triangle are equal

y^2 = 3^2 + 3^2 = 18 
y = sqrt 18  = 3 sqrt2   
5 0
3 years ago
⚠️⚠️PLEASE ANSWER QUESTION IM ALMOST DONE WITH THISSS⚠️⚠️
Komok [63]

Answer:

y-inter=6

slope=2/1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I need help with this question please I’ll mark as brainliest
Dmitriy789 [7]

Answer:

C

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (8, - 14), thus

y = a(x - 8)² - 14

To find a substitute (5, 13) into the equation

13 = a(5 - 8)² - 14

13 = a(- 3)² - 14

13 = 9a - 14 ( add 14 to both sides )

27 = 9a ( divide both sides by 9 )

a = 3

Thus

y = 3(x - 8)² - 14 → C

7 0
2 years ago
Use the relationship between the
motikmotik

The equation x° = 180° - (37°+ 53°) can be used to find the value of x.

Step-by-step explanation:

Step 1; There are three lines in the given diagram. There are a baseline and two other lines. Out of the other two lines, one extends above and below the baseline whereas the other extends only above. Since the baseline is horizontal and the others are at angles we have the sum of all the three angles as 180° i.e. 37°, x°, and 53°.

37° + x° + 53° = 180°.

Step 2; To solve the value of x, we keep the unknown value at the left-hand side whereas all the known values are taken to the right side of the equation.

x° = 180° - (37°+ 53°).

So the fifth option can be used to determine the value of x.

4 0
3 years ago
Matching Functions
Ainat [17]

Answer:

Graph A → Equation A → Table B → Property D

Graph D → Equation B → Table A → Property B

Graph B → Equation C → Table C → Property E

Graph C → Equation D → Table E → Property A

Graph E → Equation E → Table D → Property C

Step-by-step explanation:

Graph A corresponds to equation A, x·y = 2, and Table B → Property D

xy = 2 has a vertical asymptote at x = 0, and a horizontal asymptote at y = 0

y = 2/x, when x = 0, y = ∞

Graph D corresponds to equation B, -\left |  x\right | + 1 which corresponds to table A → Property B

The domain extends from (-∞, ∞), and [1, -∞)

Graph B corresponds to equation C, -(x + 2)² which gives the values in Table C and Property E wich is a horizontal shift of 2 units left and a reflection across the x-axis

Graph C corresponds to equation D, (1/3)·x - 2, which gives the values on Table E and Property A

The y-intercept of (1/3)·x - 2 = (0, -2), and the x-intercept = (6, 0)

Graph E corresponds to equation E, x³ = y, which gives the values on Table D  Property C, y is x cubed

6 0
2 years ago
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