We have been given that Susan has a 12-inch board for constructing a wooden chair.The directions say to use a board that is 29 centimeters long. We are asked to determine if Susan's board is long enough to cut or not.
We know that 1 inch is equal to 2.54 cm.
Let us convert 12 inches into cm by multiplying 12 by 2.54.


Since 12 inches is equal to 30.48 centimeters and 30.48 is greater than 29, therefore, Susan's board in long enough to cut.
Answer:
(-
, 0 )
Step-by-step explanation:
to find where the line crosses the x- axis, let y = 0 in the equation and solve for x
5x - 2(0) + 1 = 0
5x - 0 + 1 = 0
5x + 1 = 0 ( subtract 1 from both sides )
5x = - 1 ( divide both sides by 5 )
x = - 
the line crosses the x- axis at (-
, 0 ) or ( - 0.2, 0 )
The first thing we must do for this case is to find the equation of the line.

We have then:

We choose an ordered pair:

Substituting values:
From here we conclude:
Intersection with y:
We evaluate x = 0 in the function:
Slope of the line:
Point (-2, -5):
We evaluate the value of x = -2 and the value of y = -5

The equation is satisfied.
Point (8, 0):
It is part of the table, therefore belongs to the line.
Answer:
The slope is 1/2
The y-intercept is -4.
The points (-2, -5) and (8, 0) are also on the line.
Answer: 14gallons
Step-by-step explanation:
12gallons/144miles = 1gallon/12miles
Therefore 6gallons = 12*6 = 72miles.
In order to cover 240miles, she will need 240/12 = 20gallons.
20-6 = 14gallons
She will need 14gallons of gas more.
Answer:
113
Step-by-step explanation:
Let the number of adult tickets sold =a
Let the number of student tickets sold =s
A total of 259 tickets were sold, therefore:
a+s=259
Adult tickets were sold for $24 each and student tickets were sold for $16 each.
Total Revenue = $5,312
Therefore:
24a+16s=5,312
We solve the two derived equations simultaneously.
From the first equation
a=259-s
Substitute a=259-s into 24a+16s=5,312
24(259-s)+16s=5,312
6216-24s+16s=5,312
-8s=5,312-6216
-8s=-904
Divide both sides by -8
s=113
Therefore, 113 student tickets were sold.