Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
To live on campus is when you have almost like a hotel room but you may share it and it is linked to you school
Answer:
Multiply the number of inches on the map times the scale to determine the true distance. For example, if the distance on the map was 5.5 inches and the scale was 1:6,336,000, the true distance would be 550 miles. To convert an area, convert the dimensions using the scale and then find the true area.
Answer:
6x4=24 for 1 side
24x5=120 for total surface area of I'm not mistaken...
