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Dima020 [189]
3 years ago
14

What are the discontinuity and zero of the function f(x) = quantity x squared plus 5 x plus 4 end quantity over quantity x plus

4?
Discontinuity at (−4, −3), zero at (−1, 0)
Discontinuity at (−4, −3), zero at (1, 0)
Discontinuity at (4, 3), zero at (−1, 0)
Discontinuity at (4, 3), zero at (1, 0)

Mathematics
1 answer:
kap26 [50]3 years ago
4 0

Answer:

  Discontinuity at (−4, −3), zero at (−1, 0)

Step-by-step explanation:

The expression simplifies to ...

  \dfrac{x^2+5x+4}{x+4}=\dfrac{(x+4)(x+1)}{(x+4)}=x+1 \qquad\text{$x\ne -4$}

This is undefined at x=-4, hence there is a discontinuity there, and is zero for x=-1.

There is a discontinuity at x=-4, and a zero at (-1, 0).

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7000

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If d is 55 degrees then what is F and E degrees. Explain how you know​
kipiarov [429]

Answer:

F=55

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Step-by-step explanation:

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8 0
3 years ago
In a class in which the final course grade depends entirely on the average of four equally weighted 100-point tests, Joyce has s
d1i1m1o1n [39]

Answer:

66 ≤ f ≤100

Explanation

Mean= ( Σ x ) / n

Mean= sum of scores/ number of subject she took

Now, she already too 3 subject which sum is 85+83+86=254

Now we need to know range of score for her to have (grade) a mark between 80 and 89

Now let take the lower limit mean=80

The lowest score she can get is

Mean = ( Σx) / n

80=(85+83+86+f)/4

80×4= 254+f

Therefore, f= 320-254=66

Therefore the minimum score she can have to have a B is 66.

Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.

Mean = ( Σx) / n

89=( 83+85+86+f)/4

89×4= 254+f

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f=102.

Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.

There the range of score is 66 ≤ f ≤100 to have a B grade

66 ≤ f ≤100 answer

Since she cannot score 102 in the examination.

8 0
3 years ago
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