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lesantik [10]
3 years ago
13

I’m confused please help

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

im guessing the answer is 43.7

Step-by-step explanation:

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The thickness of each type of coin is shown in the table. How much thicker is stack of dollars worth of nickels than a dollars w
Lilit [14]
Let our basis be worth 1 dollar. A nickel's worth is $0.05. In order to come up with $1, the number of nickels should be:

Number of nickels = $1 * 1 nickel/$0.05 = 20 nickels
Thickness of 20 nickels = 20 nickels * 1.95 mm = 39 mm

Let's do the same for the quarters. Each quarter is worth $0.25.

Number of quarters = $1 * 1 quarter/$0.25 = 4 quarters
Thickness of 4 quarters = 4 quarters * 1.75 mm = 7 mm

Find the ratio of the two:
39 mm/7 mm = 5.57

Therefore, a stack of nickels is 5.57 times thicker than a stack of quarters worth one dollar.
7 0
4 years ago
A table.Short description, A table.,Long description, Sandwich Fat (in grams) Calories Hamburger 18 390 Cheeseburger 25 430 Baco
Oxana [17]

Using it's concept, it is found that the range of fat grams for the five sandwiches is of 24 grams.

<h3>What is the range of a data-set?</h3>

It is given by the difference of the <u>highest value by the lowest value in the data-set</u>.

In this problem, the sandwich with the least fat has 9 grams and the one with the most has 33 grams, hence the range is given by:

R = 33 - 9 = 24 grams.

More can be learned about the range of a data-set at brainly.com/question/24374080

#SPJ1

5 0
3 years ago
Find the SUm of the infinite series.
givi [52]

I'll do problem 13 to get you started.

The expression 4\left(\frac{2^n}{7^n}\right) is the same as 4\left(\frac{2}{7}\right)^n

Then we can do a bit of algebra like so to change that n into n-1

4\left(\frac{2}{7}\right)^n\\\\4\left(\frac{2}{7}\right)^n*1\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{0}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1-1}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1}*\left(\frac{2}{7}\right)^{-1}\\\\4*\left(\frac{2}{7}\right)^{1}\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{-1}\\\\\frac{8}{7}\left(\frac{2}{7}\right)^{n-1}\\\\

This is so we can get the expression in a(r)^(n-1) form

  • a = 8/7 is the first term of the geometric sequence
  • r = 2/7 is the common ratio

Note that -1 < 2/7 < 1, which satisfies the condition that -1 < r < 1. This means the infinite sum converges to some single finite value (rather than diverge to positive or negative infinity).

We'll plug those a and r values into the infinite geometric sum formula below

S = a/(1-r)

S = (8/7)/(1 - 2/7)

S = (8/7)/(5/7)

S = (8/7)*(7/5)

S = 8/5

S = 1.6

------------------------

Answer in fraction form = 8/5

Answer in decimal form = 1.6

7 0
3 years ago
Which graph represents —3x+ 5y &lt; 15?
Svetllana [295]
The top graph
hope this help
8 0
4 years ago
Read 2 more answers
How to solve inter quartile range of the given data set? 3,9,12,15,16,18,21
s2008m [1.1K]

Answer:

Step-by-step explanation:

3,9,12,(15),16,18,21

   

mean (middle number) = 15

Q1 = 9.....the middle number of the numbers before the mean

Q3 = 18...the middle number of the numbers after the mean

interquartile range (IQR) = Q3 - Q1 = 18 - 9 = 9 <==

7 0
3 years ago
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