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san4es73 [151]
3 years ago
12

Which number is the inequality m>7\12

Mathematics
2 answers:
fiasKO [112]3 years ago
4 0
7....................................................
Leokris [45]3 years ago
4 0

Answer:

The answer is the option A 1

Step-by-step explanation:

The options of the question are

A. 1  

B. -1  

C. -9  

D. -5

we have

m>\frac{7}{12}

The solution of this inequality is the interval------> (\frac{7}{12}, infinite)

All real numbers greater than \frac{7}{12}

Remember that

\frac{7}{12}=0.58 ------> using a calculator

so

m>0.58

we know that

If a number is a solution of the inequality

then

the number must satisfy the inequality

Verify each case

case A) m=1

substitute the value of m in the inequality and compare

1>0.58 ------> is true

therefore

the number m=1 is a solution

case B) m=-1

substitute the value of m in the inequality and compare

-1>0.58 ------> is not true

therefore

the number m=-1 is not a solution

case C) m=-9

substitute the value of m in the inequality and compare

-9>0.58 ------> is not true

therefore

the number m=-9 is not a solution

case D) m=-5

substitute the value of m in the inequality and compare

-5>0.58 ------> is not true

therefore

the number m=-5 is not a solution



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~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

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What is the length of the missing side , x? 22, 11, x
yulyashka [42]

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33

Step-by-step explanation:

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Answer:

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Answer:

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If the diameter is 22 ft, the radius is 11 ft.

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6 x 2 = 12mm

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5 0
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Answer: OPTION C.

Step-by-step explanation:

It is important to know the following:

<u> Dilation:</u>

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<u>Translation:</u>

  • Transformation in which the image is the same size and shape as the pre-image.
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Therefore, since the Square T was translated and then dilated to create Square T'', we can conclude that the statement that explains why  they are similar is:

<em>Translations and dilations preserve betweenness of points; therefore, the corresponding sides of squares T and T″ are proportional.</em>

6 0
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Read 2 more answers
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