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3 years ago

PLS HELP ASAP ITS A WUIZ

Mathematics

2 answers:

sukhopar [10]3 years ago

4 0

Answer:

Step-by-step explanation:

so i plugged this into a graphing calculator.. maybe it's not fair to use technology :D

vertex (1,-9)

y intercept = -8

line of symmetry is x = 1

konstantin123 [22]3 years ago

3 0

Answer:

1. (1,-9)

2. x-intercept(s): (4,0),(−2,0)

3. y-intercept(s): (0,−8)

4. By Finding the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = - 1$

Hope this helps you.... ^_^❤️

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Im just writing stuff because questions have to be atleast 20 characters long so I'm just trying to fill up some space.

DIA [1.3K]

A = 21/2 i will write something too just to fill up the space

3 0

4 years ago

-a(n)=-5+6(n-1) find the 12th term

mamaluj [8]

Answer:

Step-by-step explanation:

Put 12 where n is, then do the arithmetic.

a(12) = -5 +6(12-1) = 61

_____

We assume you didn't really mean to show an equation for -a(n). If you did, then the term you want is -61.

8 0

3 years ago

Write each decimal as a fraction .07 .051 .473 .27 .5.37 .16.49

Colt1911 [192]

Answer:

7/10

51/100

473/1000

27/100

537/1000

1649/10000

Step-by-step explanation:

im curious about what the dots are in .16.49 and .5.37, why are there two dots?

3 0

3 years ago

If 433 = 100% then what percent does 383 equal

Goryan [66]

Answer:

88.46%

Step-by-step explanation:

433 - 383 = 50

50 ÷ 433 = 0.1154

0.1154 x 100 = 11.54%

100% - 11.54% = 88.46%

Check work:

433 x 88.46% = 383

5 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

2 years ago