Hello user

To solve for V we simplify both sides of the equation then isolate the variable to get v <span>≥ 2

Therefor the answer is: </span>v ≥ 2
<span>
I hope this helped
-Chris</span>

6 0

3 years ago

Which shows the expression below simplified? 0.00028 ÷ (7 × 10-4)

Katyanochek1 [597]

$0.\underbrace{00028}_{\rightarrow5places}=28\times10^{-5}\\\\0.00028:(7\times10^{-4})=\dfrac{28\times10^{-5}}{7\times10^{-4}}=\dfrac{28}{7}\times\dfrac{10^{-5}}{10^{-4}}\\\\=4\times10^{-5-(-4)}=4\times10^{-5+4}=\huge\boxed{4\times10^{-1}}\leftarrow\boxed{b.}\\\\used\ \dfrac{a^n}{a^m}=a^{n-m}$

6 0

3 years ago

Write the equation of a piecewise function with a jump discontinuity at x =3. Then, determine which step of the 3-step test for

seraphim [82]

Answer:

Here's a possible example:

Step-by-step explanation:

$f(x) =\begin{cases} x & \quad x < 3\\x+3 & \quad x \geq 3\\\end{cases}$

Each piece is linear, so the pieces are continuous by themselves.

We need consider only the point at which the pieces meet (x = 3).

$\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) = \lim_{x \longrightarrow 3^{-}} x = 3\\\\\displaystyle \lim_{x \longrightarrow 3^{+}} f(x) = \lim_{x \longrightarrow 3^{+}} x+3 = 6\\\\f(3) = x + 3 = 6\\\\\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) \neq f(3)$

The left-hand limit does not equal ƒ(x), so there is a jump discontinuity at x =3.

5 0

3 years ago

Fifteen sprinters ran the 50-yard dash in an average of 9.5 seconds. Of those runners,3 ran the dash in 11.5 seconds. Find the a

dezoksy [38]

There might be a variety of averages for the 12 boys.

3 0

3 years ago

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