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2 years ago

Cups by the water cooler are in the shape of a cone. The height is 15 cm and the diameter is 7.6 cm.

Mathematics

1 answer:

dangina [55]2 years ago

3 0

Answer:

226.7 cm³

Step-by-step explanation:

The cone volume formula is V = (1/3)(base area)(height).

Here that comes out to V = (1/3)(pi)(3.8 cm)^2·15 cm, or 226.7 cm³

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Mike got in and elevator and whent down 3 floors. he meant to go to a lower level,so he stayed on the elevator and when down 3 m

Naily [24]

It is negative six because down three is -3 so 3+3 =6 but the numbers are negative so the answer is -6

7 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

A triangle with three acute angles and no congruent sides

Sauron [17]

The answer should be an acute scalene triangle.

Hope this helped! ♡

8 0

2 years ago

Ms. Gonzales is investing $17000 at an annual interest rate of 6%

Damm [24]

Answer:

$30444.41

Step-by-step explanation:

→ Work out compound interest

(100 + 6) ÷ 100 = 1.06

→ Multiply the amount by the money

17000 × 1.06

→ Find how many years it is for

17000 × 1.06¹⁰ = 30444.41

6 0

2 years ago

Use algebraic means to show that x^2 + y^2 = 8 is not a function. Explain your process.

11Alexandr11 [23.1K]

Answer:

For a single value of x function has more than one corresponding value of y which satisfies the equation.

Step-by-step explanation:

Function: A relationship between a set of inputs and a set of possible outputs, where exactly one output is associated with each input.

It means for an equation to represent a function any single value of x there should be only one corresponding value of y which satisfies the equation.

Now consider the given equation.

$x^2 + y^2 = 8$

If we put x=0 then we get two value of y i.e $\sqrt8$ and $-\sqrt8$ which satisfy the equation and therefore the equation is not a function.

5 0

3 years ago