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3 years ago

Why is Pluto considered less of an oddball planet now?

Physics

1 answer:

solmaris [256]3 years ago

4 0

Answer:

The International Astronomical Union (IAU) downgraded the status of Pluto to that of a dwarf planet because it did not meet the three criteria the IAU uses to define a full-sized planet. Essentially Pluto meets all the criteria except one—it “has not cleared its neighboring region of other objects

Explanation:

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The purpose of technology is to solve problems and meet needs.

Fiesta28 [93]

Answer:

Explanation:

8 0

2 years ago

Set local ground level to 700 ft, and record the inches of mercury.

pashok25 [27]

The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

<h3>How to determine the altimeter reading?</h3>

The given parameters are:

Ground level = 700 ft i.e. the field elevation
Pressure altitude = 1450 ft

The formula to calculate the pressure altitude is:

Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level

Substitute the known values

1450 = (29.92 - Altimeter reading) * 1000 + 700

Evaluate the like terms

750 = (29.92 - Altimeter reading) * 1000

Divide both sides by 1000

0.75 = 29.92 - Altimeter reading

Evaluate the like terms

Altimeter reading = 29.17

Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

Read more about pressure at:

brainly.com/question/26040104

#SPJ1

4 0

2 years ago

Help hurry help pls it’s timed

Jobisdone [24]

Answer:

its the teal/second from the left one

Explanation:

4 0

2 years ago

Read 2 more answers

A 5.30 m long pole is balanced vertically on its tip. What will be the speed (in meters/second) of the tip of the pole just befo

suter [353]

Answer:

v = 17.66 m/s

Explanation:

As we know that the lower end of the pole is fixed in the ground and it start rotating about that end

so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end

so we have

$mgL = \frac{1}{2}(\frac{mL^2}{3})\omega^2$

so we have

$\omega = \sqrt{\frac{6g}{L}}$

now we have

$\omega = \sqrt{\frac{6(9.81)}{5.30}}$

$\omega = 3.33 rad/s$

now the speed of the other tip of the pole is given as

$v = \omega L$

$v = (3.33)(5.30) = 17.66 m/s$

8 0

4 years ago

s A steel ball with mass m=5.21 g is moving horizontally with speed ????=412 m/s when it strikes a block of hardened steel with

denis23 [38]

Answer:

Vf₂ = 0.29 m/s :Speed of the block immediately after the collision.

Explanation:

Theory of collisions

Linear momentum is a vector magnitude (same direction and direction as velocity) and its magnitude is calculated like this:

P=m*v

where

p:Linear momentum

m: mass

v:velocity

There are 3 cases of collisions : elastic, inelastic and plastic.

For the three cases the total linear momentum quantity is conserved:

P₀=Pf Formula (1)

P₀ :Initial linear momentum quantity

Pf : Initial linear momentum quantity

Nomenclature and data

m₁: ball mass= 5.21 g= 5.21*10⁻³kg

V₀₁: initial ball speed, =412 m/s

Vf₁: final ball speed

m₂: block mass = 14.8 kg

V₀₂: initial block speed, = 0

Vf₂: final block speed

Problem development

For this problem the collision is perfectly elastic ,then, In addition to the linear moment, the kinetic energy is also conserved.

We assume that the ball moves to the right before the collision y continues moving to the right after the collision .(+)

We assume that the block moves to the right before the collision.(+)

We apply furmula (1)

P₀=Pf

m₁*V₀₁+m₂*V₀₂=m₁*Vf₁+m₂*Vf₂

5.21*10⁻³*412+14.8*0= 5.21*10⁻³*Vf₁+14.8*Vf₂

2.15= 5.21*10⁻³*Vf₁+14.8*Vf₂ Equation (1)

For perfectly elastic collision the coefficient of elastic restitution (e) is equal to 1, and e is defined like this:

$e=\frac{v_{f2}- v_{f1} }{v_{o1} -v_{o2} }$

1*(V₀₁-V₀₂) =Vf₂-Vf₁ , V₀₂=0, V₀₁ =412 m/s

412=Vf₂-Vf₁

Vf₁=Vf₂-412 Equation (2)

We replace Equation (2) in Equation (1)

2.15= 5.21*10⁻³(Vf₂-412)+14.8*Vf₂

2.15= 5.21*10⁻³*Vf₂-2.15+14.8*Vf₂

4.3=14.805Vf₂

Vf₂ =4.3/14.805= 0.29 m/s : (+) ,with equal direction of the movement of the ball before the collision.

8 0

3 years ago