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nika2105 [10]
3 years ago
9

Facts about Tsunami?

Physics
1 answer:
Zepler [3.9K]3 years ago
4 0
1.A tsunami is a series of ocean waves caused by an underwater earthquake, landslide, or volcanic eruption. More rarely, a tsunami can be generated by a giant meteor impact with the ocean. These waves can reach heights of over 100 ft.
2.About 80% of tsunamis happen within the Pacific Ocean’s “Ring of Fire.”
3.The first wave of a tsunami is usually not the strongest, successive waves get bigger and stronger.
4.Tsunamis can travel at speeds of about 500 miles or 805 kilometers an hour, almost as fast as a jet plane.
5.The states in the U.S. at greatest risk for tsunamis are Hawaii, Alaska, Washington, Oregon, and California.
Hope it help!
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What is the maximum force that could be applied to anterior cruciate ligament (ACL) if it has a diameter of 4.8 mm and a tensile
vovangra [49]

Answer:

Maximum force, F = 1809.55 N

Explanation:

Given that,

Diameter of the anterior cruciate ligament, d = 4.8 mm

Radius, r = 2.4 mm

The tensile strength of the anterior cruciate ligament, P=100\times 10^6\ N/m^2=10^8\ Pa

We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

F=P\times A\\\\F=10^8\times \pi (2.4\times 10^{-3})^2\\\\F=1809.55\ N

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N

4 0
3 years ago
HELP ASAP!! WILL MARK BRAINLIEST
Kitty [74]

Answer:

A

Explanation:

The magnet can always attract other things.

8 0
3 years ago
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As the army approached the bridge into the city, the commander told them to break step. He did not want the soldiers to march in
Aleks [24]

At a definite point, the bridge would begin oscillating to the matching rhythm as that of the marching footsteps. This oscillation would touch a determined peak when the bridge can no longer tolerate its own power and later collapses. So, soldiers are systematic to break their steps while passing a bridge.

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In an arcade game a 0.099 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releas
Sonja [21]

Answer:

The speed of disk is 1.98 \frac{m}{s}

Explanation:

Given:

Mass of m = 0.099 kg

Spring constant k = 244 \frac{N}{m}

Compression of spring x = 4 \times 10^{-2} m

From energy conservation theorem,

Spring potential energy converted into kinetic energy,

   \frac{1}{2} m v^{2} = \frac{1}{2} k x^{2}

  v = \sqrt{\frac{k x^{2} }{m} }

  v = \sqrt{\frac{244 \times 16 \times 10^{-4} }{0.099} }

  v = 1.98 \frac{m}{s}

Therefore, the speed of disk is 1.98 \frac{m}{s}

8 0
3 years ago
A satellite of mass M = 270kg is in circular orbit around the Earth at an altitude equal to the earth's mean radius (6370 km). A
zubka84 [21]

To solve this problem we will apply the concepts related to Orbital Speed as a function of the universal gravitational constant, the mass of the planet and the orbital distance of the satellite. From finding the velocity it will be possible to calculate the period of the body and finally the gravitational force acting on the satellite.

PART A)

V_{orbital} = \sqrt{\frac{GM_E}{R}}

Here,

M = Mass of Earth

R = Distance from center to the satellite

Replacing with our values we have,

V_{orbital} = \sqrt{\frac{(6.67*10^{-11})(5.972*10^{24})}{(6370*10^3)+(6370*10^3)}}

V_{orbital} = 5591.62m/s

V_{orbital} = 5.591*10^3m/s

PART B) The period of satellite is given as,

T = 2\pi \sqrt{\frac{r^3}{Gm_E}}

T = \frac{2\pi r}{V_{orbital}}

T = \frac{2\pi (2*6370*10^3)}{5.591*10^3}

T = 238.61min

PART C) The gravitational force on the satellite is given by,

F = ma

F = \frac{1}{4} mg

F = \frac{270*9.8}{4}

F = 661.5N

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3 years ago
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