<span>c. What is the magnitude of the tension in the string at the bottom of the circle if you are swinging it at 3.37 m/s?
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Answer:
He needs 1.53 seconds to stop the car.
Explanation:
Let the mass of the car is 1500 kg
Speed of the car, v = 20.5 m/s
He will not push the car with a force greater than, 
The impulse delivered to the object is given by the change in momentum as :
So, he needs 1.53 seconds to stop the car. Hence, this is the required solution.
The answer is true hope that helped!!
90 F = 43 OR 0.9F = 0.43
(F = 43 / 90 OR 0.43 / 0.9 =) 0.48 N
upwards force = downwards force
(R =) 1.2 N
consider the velocity towards the pitcher as positive
m = mass of the baseball = 0.145 kg
v₀ = initial velocity of the baseball = - 39 m/s
v = final velocity of the baseball = 52 m/s
t = time of contact = 3 x 10⁻³ sec
F = average force between bat and ball
Using impulse-change in momentum equation
F t = m (v - v₀ )
F (3 x 10⁻³) = (0.145) (52 - (- 39))
F = 4398.33 N
