1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nirvana33 [79]
3 years ago
7

A customer sits in an amusement park ride in which the compartment is to be pulled downward in the negative direction of a y axi

s with an acceleration magnitude of 1.24g, with g 9.80 m/s2 . a 0.567 g coin rests on the customer’s knee. once the motion be- gins and in unit-vector notation, what is the coin’s acceleration rel- ative to (a) the ground and (b) the customer? (c) how long does the coin take to reach the compartment ceiling, 2.20 m above the knee? in unit-vector notation, what are (d) the actual force on the coin and (e) the apparent force according to the customer’s meas- ure of the coin’s acceleration?
Physics
2 answers:
brilliants [131]3 years ago
6 0

Answer:

a) g = -9.8*j m/s^2

b) g = 2.35*j m/s^2

c) t = 1.37 s

d) F = - 5.56x10^-3 N*j

e) F = 1.33x10^-3 N

Explanation:

a) According to the exercise, the acceleration of the compartment is equal to:

g = -9.8*j m/s^2

b) The acceleration of the currency to the client will be equal to:

a = -1.24*g*j

F = -(m*a)

F = -(-1.24*g*j)*m = 1.24*g*j*m

The net force on coin is equal to:

Fnet = F + W = 1.24*g*m*j - m*g*j = 0.24*g*m*j

dividing the equation over m:

Fnet/m = (0.24*g*m*j)/m = 0.24*g*j = 2.35*j

c) The time it ta)akes for the coin to reach the ceiling of the compartment at a distance of 2.2 m can be calculated using the following equation:

s = u*t + (a*t^2)/2

Clearing t:

t = ((2*s)/a)^1/2 = ((2*2.2)/2.35)^1/2 = 1.37 s

d) The force on the coin is equal to:

F = -m*g, m = 0.567 g = 5.67x10^-4 kg

F = -5.67x10^-4 * (9.8*j) = - 5.56x10^-3 N*j

e) The apparent force is calculated with the following equation:

F = ma = (5.67·10^-4 kg)·(2.352 m/s²) = 1.33x10^-3 N

brilliants [131]3 years ago
3 0
(a) The coin is accelerated only by gravity (until it hits the ceiling). Its acceleration is -9.80 m/s²

(b) The acceleration relative to the customer is
  (-1.0 g) - (-1.24 g) = 0.24 g ≈ 2.352 m/s²

(c) The distance (d) covered is
  1/2at² = d . . . . for some acceleration a
  2.2 m = (1/2)(2.352 m/s²)t²
Solving for the time to cover the distance, we get
  t = √(2·2.2/2.352) s ≈ 1.368 s

(d) The actual force on the coin is that due to gravity, as found in part (a). (The first m is "mass"; the second m is "meters".)
  F = mg = (5.67·10^-4 kg)·(-9.8 m/s²) = -5.5566·10^-3 N

(e) From the customer's point of view, the apparent force on the coin is
  F = ma = (5.67·10^-4 kg)·(2.352 m/s²) = 1.333584·10^-3 N
(The positive sign means directed upward.)
You might be interested in
How could you decrease the total energy of a system consisting of a jar full of water? O A. Heat the jar in a microwave oven. O
Vaselesa [24]

Answer:

A

Explanation:

6 0
3 years ago
Read 2 more answers
A conglomerate is a rock that forms as a result of _____. . . Choices:Intense heat and pressure. Compaction and cementation. Rap
sergeinik [125]

A conglomerate is a rock that forms as a result of compaction and cementation. The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

7 0
3 years ago
Read 2 more answers
You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts,
g100num [7]

Answer:

T = 29.66 ^o C

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

ms \Delta T = m' L

so here we have

0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)

T = \frac{2512.5}{0.220 \times 385}

T = 29.66 ^o C

5 0
3 years ago
Which lab equipment is used as a cover to prevent heated materials from splattering out of the container and as a holding plate
faltersainse [42]

Watchglass is a lab equipment that is used as a cover to prevent heated materials from splattering out of the container and as a holding plate for hot or flammable materials

<u>Explanation:</u>

Watch glass is an equipment used as a cover to prevent heated materials from splattering out of the container and as a holding plate for hot or flammable materials. It is a kind of concave glass which is also used to evaporate a liquid and also provides good air circulation which is used during cooking. The name watchglass was derived as they are see through and so similar to pocket glasses.

3 0
3 years ago
Four identical masses m are evenly spaced on a frictionless 1D track. The first mass is sent at speed v toward the other three.
SpyIntel [72]

Answer:

The speed decreases 75%.

Explanation:

  • Since no friction present, assuming no external forces acting during the three collisions, total momentum must be conserved.
  • For the first collission, only mass 1 is moving before it, so we can write the following equation:

       p_{i} = p_{f} = m*v_{o}    (1)

  • Since both masses are identical, and they stick together after the collision, we can express the final momentum as follows:

       p_{f1} = 2*m*v_{1}    (2)

  • From (1) and (2) we get:
  • v₁ = v₀/2  (3)
  • Since the masses are moving on a frictionless 1D track, the speed of the set of mass 1 and 2 combined together before colliding with mass 3 is just v₁, so the initial momentum prior the second collision (p₁) can be expressed as follows:

       p_{1} = 2*m*v_{1} = 2*m*\frac{v_{o} }{2}  = m*v (4)

  • Since after the collision the three masses stick together, we can express this final momentum (p₂) as follows:

        p_{2} = 3*m*v_{2}  (5)

  • From (4) and (5) we get:
  • v₂ = v₀/3  (6)
  • Since the masses are moving on a frictionless 1D track, the speed of the set of mass 1, 2 and 3 combined together before colliding with mass 4 is just v₂, so the initial momentum prior the third collision (p₂) can be expressed as follows:

      p_{2} = 3*m*v_{2} = 3*m*\frac{v_{o} }{3}  = m*v (7)

  • Since after the collision the four masses stick together, we can express this final momentum (p₃) as follows:

       p_{3} = 4*m*v_{3}  (8)

  • From (7) and (8) we get:
  • v₃ = v₀/4
  • This means that after the last collision, the speed will have been reduced to a 25% of the initial value, so it will have been reduced in a 75% regarding the initial value of v₀.
5 0
2 years ago
Other questions:
  • What relation does the boiling point of an amine have to a similar hydrocarbon?
    14·2 answers
  • Which has a larger resistance a 60 w lightbulb or a 100 w lightbulb?
    14·1 answer
  • The majority of pelagic sediments are of which type?
    14·1 answer
  • A sample neon gas has its volume tripled and its temperature held constant. What will be the new pressure relative to the initia
    5·1 answer
  • How many mL of beakers u need in separating salt, sand, iron filings, and beads
    9·1 answer
  • Which index of refraction represents the most optically dense material?
    14·2 answers
  • What do hydroelectric plants use to generate electrical energy?
    7·2 answers
  • Without the greenhouse effect operating in our atmosphere
    8·2 answers
  • A garden roller is pulled with a force of 200N, acting at an angle of 50 degree with the ground level.find the force pulling the
    9·1 answer
  • Describe an example of acceleration and explain how velocity is changing.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!