1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nirvana33 [79]
3 years ago
7

A customer sits in an amusement park ride in which the compartment is to be pulled downward in the negative direction of a y axi

s with an acceleration magnitude of 1.24g, with g 9.80 m/s2 . a 0.567 g coin rests on the customer’s knee. once the motion be- gins and in unit-vector notation, what is the coin’s acceleration rel- ative to (a) the ground and (b) the customer? (c) how long does the coin take to reach the compartment ceiling, 2.20 m above the knee? in unit-vector notation, what are (d) the actual force on the coin and (e) the apparent force according to the customer’s meas- ure of the coin’s acceleration?
Physics
2 answers:
brilliants [131]3 years ago
6 0

Answer:

a) g = -9.8*j m/s^2

b) g = 2.35*j m/s^2

c) t = 1.37 s

d) F = - 5.56x10^-3 N*j

e) F = 1.33x10^-3 N

Explanation:

a) According to the exercise, the acceleration of the compartment is equal to:

g = -9.8*j m/s^2

b) The acceleration of the currency to the client will be equal to:

a = -1.24*g*j

F = -(m*a)

F = -(-1.24*g*j)*m = 1.24*g*j*m

The net force on coin is equal to:

Fnet = F + W = 1.24*g*m*j - m*g*j = 0.24*g*m*j

dividing the equation over m:

Fnet/m = (0.24*g*m*j)/m = 0.24*g*j = 2.35*j

c) The time it ta)akes for the coin to reach the ceiling of the compartment at a distance of 2.2 m can be calculated using the following equation:

s = u*t + (a*t^2)/2

Clearing t:

t = ((2*s)/a)^1/2 = ((2*2.2)/2.35)^1/2 = 1.37 s

d) The force on the coin is equal to:

F = -m*g, m = 0.567 g = 5.67x10^-4 kg

F = -5.67x10^-4 * (9.8*j) = - 5.56x10^-3 N*j

e) The apparent force is calculated with the following equation:

F = ma = (5.67·10^-4 kg)·(2.352 m/s²) = 1.33x10^-3 N

brilliants [131]3 years ago
3 0
(a) The coin is accelerated only by gravity (until it hits the ceiling). Its acceleration is -9.80 m/s²

(b) The acceleration relative to the customer is
  (-1.0 g) - (-1.24 g) = 0.24 g ≈ 2.352 m/s²

(c) The distance (d) covered is
  1/2at² = d . . . . for some acceleration a
  2.2 m = (1/2)(2.352 m/s²)t²
Solving for the time to cover the distance, we get
  t = √(2·2.2/2.352) s ≈ 1.368 s

(d) The actual force on the coin is that due to gravity, as found in part (a). (The first m is "mass"; the second m is "meters".)
  F = mg = (5.67·10^-4 kg)·(-9.8 m/s²) = -5.5566·10^-3 N

(e) From the customer's point of view, the apparent force on the coin is
  F = ma = (5.67·10^-4 kg)·(2.352 m/s²) = 1.333584·10^-3 N
(The positive sign means directed upward.)
You might be interested in
The following questions consist of a statement and a reason .Answer these questions selecting the appropriate options given belo
Mamont248 [21]

Answer:

<em><u>1)A)</u></em>

<em><u>1)A)2)A)</u></em>

<h3><em><u>Hope it helps you </u></em><em><u>♡</u></em><em><u>♡</u></em></h3>

4 0
3 years ago
Lab: Thermal Energy Transfer What is the purpose of the lab, the importance of the topic, and the question you are trying to ans
VladimirAG [237]

Answer:

it's important because it shows how thermal energy transforms or continues to be all around us in everything

6 0
3 years ago
WILL GIVE BRAINLIEST ASAP
Sedaia [141]

Explanation:

1. Height Relatives to reference point, Mass, and strength of the gravitational field it's in

2. Distance in the magnetic field

8 0
2 years ago
Question 5 of 10
muminat
The correct answer to this question is D
5 0
3 years ago
An ideal heat engine absorbs 97.2 kJ of heat and exhausts 83.8 kJ of heat in each cycle. What is the efficiency of the engine?
r-ruslan [8.4K]

Answer:

13.7%

Explanation:

Given that,

Heat absorbed by the engine = 97.2 kJ

Heat exhausted by the engine in each cycle = 83.8 kJ

We need to find the efficiency of the engine. It is calculated by the formula.

\eta=1-\dfrac{Q_e}{Q_a}\\\\=1-\dfrac{83.8}{97.2}\\\\=0.137\\\\=13.7\%

so, the efficiency of heat engine is 13.7%.

5 0
3 years ago
Other questions:
  • A 2 ft x 2 ft x 2 ft box weighs 100 pounds, and the weight is evenly distributed. What is the magnitude of the minimum horizonta
    9·2 answers
  • What parts are found in an electric generator
    14·2 answers
  • A 3.25 kg block is sent up a ramp inclined at an angle θ = 32.5 ° from the horizontal. It is given an initial velocity v 0 = 15.
    5·1 answer
  • A satellite of mars, called phobos, has an orbital radius of 9.4 106 m and a period of 2.8 104 s. assuming the orbit is circular
    6·2 answers
  • While riding in a moving car, you toss an egg directly upward. Does the egg tend to land behind you, in front of you, or back in
    15·1 answer
  • an object moving North with an initial velocity of 14 m s accelerates 5 Ms ^2 for 20 seconds what is the final velocity of the o
    12·2 answers
  • It takes 23 hours 56 minutes and 4 seconds for the earth to make one revolution (mean sidereal day). What is the angular speed o
    14·1 answer
  • The mass of an object changes as the distance from the center of gravity changes. True False
    7·2 answers
  • A wrecking ball is suspended by two cables as shown below. If the tension in cable 2 is 12 000 N, what is the weight of the wrec
    12·1 answer
  • The maximum electric field strength in air is 3.0 Mv/m . Stronger electric fields ionize the air and create a spark. What is the
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!