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Verdich [7]
3 years ago
11

NEED HELP NOW!!!!!!!!

Chemistry
1 answer:
slega [8]3 years ago
5 0

Answer:

cooling of surroundings

Explanation:

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Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B
eimsori [14]
2 boxes of A
Because C = A + B
2 of A = 20 grams
at the other hand we have 2 of B = 10
So 20 + 10 = 30 grams
3 0
4 years ago
Pls help question and answers in picture <br> Will make you brainliest <br> TYYYY
Burka [1]

Answer:

g

Explanation:

g

7 0
3 years ago
Read 2 more answers
How do i write a c-e-r for this
Maurinko [17]

Answer: it’s B for edge !

Explanation: took the test

4 0
3 years ago
If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be
Korvikt [17]

Answer:30 L

Explanation:

Initial Volume

=

V

1

=

60

l

i

t

e

r

Initial Temperature

=

T

1

=

546

K

Final Temperature

=

T

2

=

273

K

Final Vloume

=

V

2

=

?

?

Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,

V

1

T

1

=

V

2

T

2

⇒

V

2

=

V

1

⋅

T

2

T

1

=

60

⋅

273

546

=

60

2

=

30

l

i

t

e

r

⇒

V

2

=

30

l

i

t

e

r

Hence the new volume of the gas is

30

l

i

t

e

r

6 0
3 years ago
Concentration of Cl ion of 72.24g NaCl in .862 L solution
Nady [450]

Answer:

Molarity_{Cl^-}=1.434\ M

Explanation:

Moles of NaCl :

Given, Mass of NaCl = 72.24 g

Molar mass of NaCl = 58.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{72.24\ g}{58.44\ g/mol}

Moles\ of\ NaCl= 1.2361\ mol

NaCl is a strong salt. So, moles of chloride ion = 1.2361 moles

Volume = 0.862 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{Cl^-}=\frac{1.2361}{0.862}

Molarity_{Cl^-}=1.434\ M

7 0
3 years ago
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