How do i write a c-e-r for this

Chemistry

1 answer:

Maurinko [17]3 years ago

4 0

Answer: it’s B for edge !

Explanation: took the test

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The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon

tigry1 [53]

Answer:

$\boxed{\text{300 g}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32 60

CH₃OH + CO ⟶ CH₃COOH

m/g: 160

(a) Moles of CH₃OH

$\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}$

(b) Moles of CH₃COOH

$\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}$

(c) Mass of CH₃COOH

$\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}$

3 0

4 years ago

2Fe2O3 + 3C → 4Fe + CO2 <br><br> IS this a balanced equation?

Dima020 [189]

Answer:

Explanation:

In the left side of the reaction, there are 6O and 3C but on the right side, there are only 1C and 2O

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3 years ago

A preliminary untested explanation that tries to explain how or why things happen in the manner observed is a scientific

icang [17]

It is a scientific hypothesis. A scientific hypothesis must be testable, however there is a significantly more grounded necessity that a testable speculation must meet before it can truly be viewed as logical. This foundation comes essentially from crafted by the rationalist of science Karl Popper, and is called "falsifiability".

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4 years ago

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11111nata11111 [884]

Rock a is a sedimentary and rock B is a sediment rock also known as sandstone

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3 years ago

Calculate the moles of HCl in 15 mL of a 0.50 M solution.

Verizon [17]

Explanation:

$\tiny\implies Molarity = \dfrac{no. \: of \: moles \: of \: solute \times 1000}{volume \: of \: the \: solution \: (in \: ml)}$