Question

Concentration of Cl ion of 72.24g NaCl in .862 L solution

Answer 1

Answer:

$Molarity_{Cl^-}=1.434\ M$

Explanation:

Moles of NaCl :

Given, Mass of NaCl = 72.24 g

Molar mass of NaCl = 58.44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{72.24\ g}{58.44\ g/mol}$

$Moles\ of\ NaCl= 1.2361\ mol$

NaCl is a strong salt. So, moles of chloride ion = 1.2361 moles

Volume = 0.862 L

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity_{Cl^-}=\frac{1.2361}{0.862}$

$Molarity_{Cl^-}=1.434\ M$