The amount of heat needed would be the specific heat multiplied by the mass of the substance and the temperature difference. In this case, the mass would be 75.0–g, the specific heat would be 0.449 j/g °c, and the temperature difference would be <span>1535 -25= 1510
Then the calculation would be: </span>0.449 j/g °c * 75g * 1510°c = 50,849.25J
In calorie it would be: 50849.25J / 4.184J/cal= 12,153.26 calorie
Answer:
this website should help , put the numbers in and it'll do it for you
https://calculator.academy/mass-percent-calculator/
The question deals with isotopes and how their masses differ from their normal elemental counterparts.
Here, T represents tritium, which is an isotope of hydrogen with a mass of 3 amu. Similarly, the isotope of oxygen present is ¹⁷O, which means it has a mass of 17 amu.
To determine the mass of this molecule, we do the following calculation:
3 * 2 + 17 * 2
6 + 34
40
The mass of T₂¹⁷O₂ is 40 amu