Answer:
W_net = mg + 2mgh/r
Explanation:
The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.
Now, gravitational force is; F_g = mg
While centripetal force is; F_c = mv²/r
Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.
Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.
Thus;
F_c = 2mgh/r
Where;
m is ball mass
r is tube radius
h is fall height
Thus, the net force will be;
F_net = F_g + F_c
Now, Net force would be equal to the net weight that will be read on the scale.
Thus;
W_net = F_net = F_g + F_c
W_net = mg + 2mgh/r
Answer:
Kinematics is the study of how things move while dynamics is the study of forces and motion
It should be gown, mask, gloves, and then goggles!
Answer:
U₂ = 20 J
KE₂ = 40 J
v= 12.64 m/s
Explanation:
Given that
H= 12 m
m = 0.5 kg
h= 4 m
The potential energy at position 1
U₁ = m g H
U₁ = 0.5 x 10 x 12 ( take g= 10 m/s²)
U₁ = 60 J
The potential energy at position 2
U₂ = m g h
U ₂= 0.5 x 10 x 4 ( take g= 10 m/s²)
U₂ = 20 J
The kinetic energy at position 1
KE= 0
The kinetic energy at position 2
KE= 1/2 m V²
From energy conservation
U₁+KE₁=U₂+KE₂
By putting the values
60 - 20 = KE₂
KE₂ = 40 J
lets take final velocity is v m/s
KE₂= 1/2 m v²
By putting the values
40 = 1/2 x 0.5 x v²
160 = v²
v= 12.64 m/s
Sound waves!!!!!!!!!!!!!!!