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sineoko [7]
3 years ago
14

Light behaves:

Physics
2 answers:
yuradex [85]3 years ago
3 0

Answer:

b..................m..

Brrunno [24]3 years ago
3 0

\pmb{\boxed{Answer:- }}

Light behaves <u>Sometimes as a wave sometime as a particle</u><u>.</u>

<em>It</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>dual</em><em> </em><em>nature</em><em> </em><em>of</em><em> </em><em>light</em><em>.</em>

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A factor that determines the inertia of an object is
Mars2501 [29]
Height, weight, size
7 0
3 years ago
A 235 kg motorcycle moves with a velocity of 7 m/s. What's it's kenetic energy?
antiseptic1488 [7]
The non-relativistic formula for low speed  v < 0.1c is:

K.E = 0.5mv^2 = 0.5 * 235 * (7)^2 = 5757.5 J
7 0
4 years ago
A 15.0-Ω resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed swit
Aloiza [94]

Answer:

0.04328 H

0.00288 seconds

0.01326 seconds

Explanation:

V = Voltage = 6.3 V

R = Resistance = 15 Ω

L = Inductance

I = Decayed current = 0.21 A

t = Time to decay = 2 ms

Maximum Current is given by

I_0=\frac{V}{R}\\\Rightarrow I_0=\frac{6.3}{15}\\\Rightarrow I_0=0.42\ A

Current in the circuit is given by

I=I_0exp\frac{-Rt}{L}\\\Rightarrow ln\frac{I_0}{I}=\frac{Rt}{L}\\\Rightarrow L=\frac{Rt}{ln\frac{I_0}{I}}\\\Rightarrow L=\frac{15\times 2\times 10^{-3}}{ln\frac{0.42}{0.21}}\\\Rightarrow L=0.04328\ H

The inductance is 0.04328 H

Time constant is given by

\tau=\frac{L}{R}\\\Rightarrow \tau=\frac{0.04328}{15}\\\Rightarrow \tau=0.00288\ s

Time constant is 0.00288 seconds

Time required is given by

t=\tau ln\frac{I_0}{I}\\\Rightarrow t=0.00288\times ln\frac{I_0}{0.01I_0}\\\Rightarrow t=0.01326\ s

The time to reach 1% of its original value is 0.01326 seconds

7 0
4 years ago
To pull a box up a rough slope,the force required will be least when it is applied :
kaheart [24]

Answer:

The correct option is;

d) Parallel to the plane

Explanation:

The forces acting on the box of mass, m are;

Weight of the box acting an angle, θ, equal to the inclination of the plane to the perpendicular of the plane

Weight of the box acting along the plane = m×g×sin(θ)

The force of friction along the plane = μ×m×g×cos(θ)

The total force acting downward along the plane F_{down}, = m×g×sin(θ) + μ×m×g×cos(θ)

The Force needed to pull the box up along the plane F = The total force acting downward along the plane

F = m×g×sin(θ) + μ×m×g×cos(θ) = m×g×(sin(θ) + μ×cos(θ))

When the force, Fₐ is applied vertically, the force acting along the plane = Fₐ×cos(θ)

When the force is applied perpendicular, the force acting along the plane = Fₐ×sin(θ)

When the force is applied horizontally, the force acting along the plane = Fₐ×cos(θ)

When the force is applied parallel to the plane, the force acting along the plane = Fₐ

Therefore, since Fₐ > Fₐ×cos(θ) and Fₐ > Fₐ×sin(θ), for acute angles, we have that the least force is required when the force is acting parallel to the plane.

6 0
3 years ago
The initial momentum and the vertical and horizontal component
tamaranim1 [39]
Momentum = mass * velocity

p = mv

p = 1.5 kg * 40 ms^-1

p = 60 kgm/s

To find components of a vector:

px = p * cos(theta)
px = 60 * cos(30)
px = 51.96 = 52 (rounded to two significant digits)

py = p * sin(theta)
py = 60 * sin(30)
py = 30

He initial momentum is 60kgm/s
The horizontal component is 52 kgm/s
The vertical component is 30 kgm/s
8 0
3 years ago
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