the length of a rectangle is 3 times the width the perimeter of rectangle is 44cm. what is the length and the width?

ZE is the angle bisector of measure YEX and the perpendicular bisector of GF, GX is the angle bisector of measure YGZ and the pe

den301095 [7]

Answer:

C

Step-by-step explanation:

The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.

The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.

Circumscribed circle always passes through the vertices of the triangle.

Inscribed circle is always tangent to the triangle's sides.

In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.

7 0

3 years ago

Devin started the work shown to solve for the unknown angle measures. 8x – 1 + 9x – 6 = 180 17x – 7 = 180 17x = 187 What are the

makvit [3.9K]

Answer:

$m$

Step-by-step explanation:

we have that

$m$

$m$ ------> by supplementary angles

Substitute the values and solve for x

$8x-1+9x-6=180\°$

$17x-7=180\°$

$17x=187\°$

$x=11\°$

Find the value of angle R

$m$

Find the value of angle Q

$m$

6 0

3 years ago

Read 2 more answers

You have 100 cm of string which can be cut in one place (or not cut at all) and then formed into a circle and a square (or just

Ne4ueva [31]

Answer:

44cm for minimum area and 0 for maximum area (circle)

Step-by-step explanation:

Let's C be the circumference of the circle and S be the circumference of the square. If we cut the string into 2 pieces the total circumferences would be the string length 100cm.

S + C = 100 or S = 100 - C

The side of square is S/4 and radius of the circle is $\frac{C}{2\pi}$

So the area of the square is

$A_S = \frac{S^2}{4^2} = \frac{S^2}{16}$

$A_C = \pi\frac{C^2}{(2\pi)^2} = \frac{C^2}{4\pi}$

Therefore the total area is

$A = A_S + A_C = \frac{S^2}{16} + \frac{C^2}{4\pi}$

We can substitute 100 - C for S

$A = \frac{(100 - C)^2}{16} + \frac{C^2}{4\pi}$

$A = \frac{100^2 - 200C + C^2}{16} + \frac{C^2}{4\pi}$

$A = 625 -12.5C + \frac{C^2}{16} + \frac{C^2}{4\pi}$

$A = 625 -12.5C + C^2(\frac{1}{16} + \frac{1}{4\pi})$

To find the maximum and minimum of this, we can take the first derivative and set that to 0

$A^{'} = -12.5 + 2C(\frac{1}{16} + \frac{1}{4\pi}) = 0$

$C(\frac{1}{8} + \frac{1}{2\pi}) = 12.5$

$C \approx 44 cm$

If we take the 2nd derivative:

$A^{''} = \frac{1}{8} + \frac{1}{2\pi} > 0$

We can see that this is positive, so our cut at 44 cm would yield the minimum area.

The maximum area would be where you not cut anything and use the total string length to use for either square or circle

if C = 100 then $A_C = \frac{C^2}{4\pi} = \frac{100^2}{4\pi} = 795.77 cm^2$

if S = 100 then $A_S = \frac{S^2}{16} = \frac{100^2}{16} = 625 cm^2$

So to yield maximum area, you should not cut at all and use the whole string to form a circle

4 0

3 years ago

Find the first, fourth, and eight terms of the sequence: A(n)=-5•3n-1

lys-0071 [83]

A (1)= -5×3(1)-1

a(1)= -5×3-1

a (1)= -16

A(4)= -5×3(4)-1

a (4)= -5×12-1

a( 4) = -60-1

a(4)= -61

A(8)= -5×3(8)-1

a(8)= -5×24-1

a(8)= -120-1

a(8)= -121

Please vote my answer branliest! Thanks.

6 0

3 years ago

From the observation deck of a skyscraper, Micaela measures a 45° angle of

EleoNora [17]

Answer:

870

Step-by-step explanation:

The angle we are focusing on is 45 degrees and we are given vaules/variables for the opposite and adjecent of the triangle. This means we use tangent. The opposite of the triangle is 870 and the adjacent is the unknown (x). The equation then simplifies to

tan(45)=870/x

tan(45)x=870

870/tan(45)=x

if you plug this into the caluclator you get 870.

8 0

2 years ago