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Nataliya [291]
3 years ago
12

1. The school office is now selling neon mechanical pencils. If the office pays $10.80 for a dozen pencils, how much should be c

harged to make a profit of 75 cents each?
2. Several cases of 16-ounce bottles of water were purchased for $252.00. If one case costs $7.00, how many cases were purchased?
3. Okolona College ordered jerseys to sell at the homecoming game. The college paid $9.25 each for 225 jerseys. Each jersey was sold for $15.75. What was the percent of markup for each jersey? How much profit was made if all of the jerseys were sold?
4. A truck traveled 654 miles on a long distance run. If the truck averaged 55 mph, how many hours did it take to reach the truck's destination? (Round to the nearest hour)
5. Della Riley borrowed $2400 for 6 months to invest in a business venture. If she agreed to pay 8% interest annually, how much will she be repaying?
6. It takes Dan an average of 45 minutes each evening to do his chemistry homework. Dan calculates that he worked a total of 3 hours on chemistry last week. Assuming that Dan worked his average time per evening consistently, how many evenings did Dan work?
7. Jon's car averages 20 mpg in town and 28 mpg on the road. What is the percent of decrease between the two driving conditions?
Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

1. Each pencil cost .90 cents each. So if they want to make a profit of 75 cents each they will get $9 for a dozen pencils. They must charge 75 cents.

2.  Several means 4 but in this case, it means 36. When you divide 252 by 7 you get 36. Because each case is $7 and the total is 252.

3. The percent markup for each jersey was around 65%. They almost doubled the price by 6.50. They would make $3543.75 if they sold all the jerseys at the homecoming game.

4. The truck took 12 hours to reach its destination.

5. She would be repaying $ 1,152.00 in one year.

I hope this helps. I did not do 6 and 7 because I hope these help you figure those out. : )

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If the probabilities of A, B, and A or B are 0.4, 0.26, and 0.436. Then the probability of A and B will be 0.224.

<h3>What is the addition rule of size for two subsets?</h3>

For two subsets A and B of the universal set U, we have:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Then the expression can be written as

P(A ∩ B) = P(A) + P(B) - P(A ∪ B)

The probabilities are given below.

P(A) = 0.4

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P(A ∪ B) = 0.436

Then the probability of A and B will be

P(A ∩ B) = P(A) + P(B) - P(A ∪ B)

P(A ∩ B) = 0.4 + 0.26 - 0.436

P(A ∩ B) = 0.66 - 0.436

P(A ∩ B) = 0.224

Learn more about the addition rule for two subsets here:

brainly.com/question/27496136

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What is the sign of the product (–5)(–3)(–8)(–6)? Positive, because the products (–5)(–3) and (–8)(–6) are negative, and the pro
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  Positive, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive

Step-by-step explanation:

There are an even number of negative factors, so the product is positive:

  Positive, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive

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1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111122222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333344444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444444445555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555566666666666666666666666666666666666666666666666666666666666666666666666666666677777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777777888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888888999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

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