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3 years ago

5

Priya completed 9 exam questions. This is 60% of the questions on the exam.

1 answer:

Naily [24]3 years ago

8 0

A and B.

60/100 • p = 9 will give you 60 % of the test questions

0.6p = 9 will also give you 60% of the test questions

60 - p = 9 will take away 60 questions from the test making it wrong

60+p = 9 will add 60 questions to the test making it wrong

9+p = 60 will add 9 questions to the test making it wrong

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Please solve this equations y=6x²-5,y=17x-6/x

Amiraneli [1.4K]

Answer:

$x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31$

Step-by-step explanation:

$y=6x^2-5\\y=17x-\frac{6}{x}$

Let's substitute the first equation into the second one.

$6x^2-5=17x-\frac{6}{x}$

$6x^3-17x^2-5x+6=0$ - Multiply by $x$ and bring all the terms to one side.

I'll use my graphical calculator to solve this but you could factor:

$x=3\\x=0.5\\x=-0.67$ (All rounded to 2 decimal places)

Now we can substitute these $x$ values into an equation for $y$ .

$y=6x^2 - 5$

$x=3, y = 49\\x=0.5, y = -3.5\\x=-0.67, y = -2.31$

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Step-by-step explanation:

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2 years ago

At a candy store, Erika bought 3 kilograms of cinnamon red hors and 1 kilogram of gummy bears for $21.00. Meanwhile, trene bough

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The cost of one kilogram of cinnamon red hots is $4.00 and cost of one kilogram of gummy bears is $9.00

Step-by-step explanation:

Let,

Cost of one kilogram of cinnamon red hots = x

Cost of one kilogram of gummy bears = y

According to given statement;

3x+y=21 Eqn 1

3x+3y=39 Eqn 2

Subtracting Eqn 1 from Eqn 2

$(3x+3y)-(3x+y)=39-21\\3x+3y-3x-y=18\\2y=18$

Dividing both sides by 2

$\frac{2y}{2}=\frac{18}{2}\\y=9$

Putting y=9 in Eqn 1

$3x+9=21\\3x=21-9\\3x=12$

Dividing both sides by 3

$\frac{3x}{3}=\frac{12}{3}\\x=4$

The cost of one kilogram of cinnamon red hots is $4.00 and cost of one kilogram of gummy bears is $9.00

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

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