D'(-3,-4)
E'(-3,-10)
F'(3,-6)
M=(y2-y1)/(x2-x1) <em>(Multiplied terms on both sides of equation by (x2-x1).)</em>
m(x2-x1)=y2-y1 <em>(Added y1 to both sides of equation, ultimately isolating y2.)</em>
y2=m(x2-x1)+y1
Answer:
168 hope this is right
Step-by-step explanation: