$\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4$

{L'Hospital's rule}

<em>I hope this helps you</em>

6 0

1 year ago

Please help for eleven points

Arlecino [84]

C: B:

3 0

6 9

9 18

12 27

All you had to do was plug in the value for c or b and solve. You can tell this is most likely correct because you see patterns for both variables. C is going up by threes, while b is going up by nines.

3 0

2 years ago

Question: A canary's beak is, at most, 20mm long. Which algebraic inequality represents this situation?

Paul [167]

Answer:

Option (1).

Step-by-step explanation:

Statement given states that "A canary's beak is, at most 20 mm long."

Word "at most" means "the maximum".

So at most length of the beak means "length of the beak is less than equal to 20 mm".

And the expression representing this statement algebraically will be,

x ≤ 20

Therefore, option (1) will be the correct option.

8 0

2 years ago

A florist normally takes 20 hours to assemble 10 flower arrangements how long do it takes to do one flower arrangement

Mariana [72]

20/10= 2

All you need to do is divide the number of hours it takes by the number of flower arrangments. So, it takes the florist 2 hours to assemble one flower arrangement.

I hope this helps!
~kaikers

5 0

2 years ago