The answer is the second option
For question number 3
-7, 7, 6, -4,
4, -2, -1, 1
0, 2, 3, -3,
5, -5, -6, 8
For question number 4:
-4, 1, -10, 3,
-9, 2, -3, 0,
5, -8, -1, -6,
-2, -5, 4, -7
Answer:
Cost of adult ticket = $12.5
Cost of child ticket = $7.5
Step-by-step explanation:
Given:
Cost of 6 adult ticket and 5 child ticket = $112.5
Cost of 8 adult ticket and 4 child ticket = $130
Find:
Equation and solution
Computation:
Assume;
Cost of adult ticket = a
Cost of child ticket = b
So,
6a + 5b = 112.5....eq1
8a + 4b = 130 ......eq2
Eq2 x 1.25
10a + 5b = 162.5 .....eq3
eq3 - eq1
4a = 50
Cost of adult ticket = $12.5
8a + 4b = 130
8(12.5) + 4b = 130
Cost of child ticket = $7.5
This shape is separated into two trapezoids. The equation for the area of a trapezoid is .5(base1 + base2) multiplied by height. Therefore, each half of the compound shape would be equal to .5(12 + 8) * 6 or 10 * 6 = 60. So the area of the total would be 60+60 or 120.
This one is prime. The sum of two squares doesn't factor.
The more interesting case is q^2-1, which factors into (q-1)(q+1).
