Answer:
George's mistake would be:
Instead of 2x + 40, she has made - x + 20.
Step-by-step explanation:
Slope - Intercept Form = y = mx + b
y + 20 = 2(x +20)
y + 20 = 2x + 40
- 20 - 20
----------------------
y = 2x + 20
(Should have been the answer)
BUT,
George's Solving:
y + 20 = 2(x + 20)
y + 20 = -x + 20
George's Mistake would be her miscalculation during her 2nd step. Where instead of distributing 2 to (x + 20), she has changed it to -x + 20, when in reality, it should have been 2x + 40.
Answer:
15 grams and 15000 milligrams
Step-by-step explanation:
Answer: Im pretty sure thats associative property.
Answer:
Step-by-step explanation:
Use the exponential form of this log equation. Rewriting this into exponential form gives us
5-squared is 25, so
25 = 2x - 3 and
22 = 2x so
x = 11
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
