Using the relation between velocity, distance and time, it is found that t = 3 hours.
<h3>What is the
relation between velocity, distance and time?</h3>
Velocity is <u>distance divided by time</u>, hence:
For this problem, the parameters are given as follows:
d = 15 miles, v = 5 mph
Hence the time in hours is found as follows:
5t = 15
t = 15/5
t = 3 hours.
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Answer:
(x) = 
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = 5x + 4 ( subtract 4 from both sides )
y - 4 = 5x ( divide both sides by 5 )
= x
change x to (x) and y back to x, thus
(x) =
Eli lives closer to his friends house than his school
With the help of the given equation, we know that the automobile is worth $12528.15 after four years.
<h3>
What are equations?</h3>
- A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
- a formula that expresses the connection between two expressions on each side of a sign.
- Typically, it has a single variable and an equal sign.
- Like this: 2x - 4 Equals 2.
- In the above example, the variable x exists.
So, the equation of depreciation: y = A(1 - r)∧t
The current value is y.
A is the initial cost.
r is the depreciation rate.
t is the time in years, and
In four years, we must ascertain the present value.
Now,
y = $24000(1 - 0.15)⁴
y = 24000(0.85)⁴
y = 24000 × 0.52200625
y = 12528.15
Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.
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Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $
You have to ask yourself how would you read that decimal? It is 162 ten-thousandths because the last digit, which is 2 is in the ten-thousandths place. So the fraction would be 162/10000
