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3 years ago

Question in pic! help asapp! will give brainliest!

Mathematics

2 answers:

Nataliya [291]3 years ago

4 0

The answer is D yw :)

Yuliya22 [10]3 years ago

3 0

Answer:

4/x^7

Step-by-step explanation:

4x^-7 = 4* x^-7 = 4* 1/x^7 = 4/x^7

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Please help and answer why

Brilliant_brown [7]

2 sticks of butter

5-1=4

4/2=2

She already makes 1 cake so we can subtract 5-1

2 cakes can be made per stick of butter so we do 4/2 which is 2

8 0

3 years ago

Two pools are leaking, after 15 minutes pool A has leaked 2/3 gallon, after 20 minutes pool B has leaked 2/3 gallon. Which pool

shepuryov [24]

Answer:

Pool A.

Step-by-step explanation:

This can be solved through ratios. You would write it as $\frac{gallons}{minutes}$ So, $\frac{2/3}{15}$ for the first one, and $\frac{2/3}{20}$ for the second. You might want to use a calculator for that part, but you could also change the gallons to cups, which gives you a much better number of 10.515. So, $\frac{10.515}{15} = 0.701$ , and $\frac{10.515}{20} = 0.52575$ So, pool A is at a faster rate. If you want it in gallons per minute, it's by 0.01 (with the 1 repeating) gallons per minute. By cups, it's 0.17525 cups per minute.

(The reason I did not do this by cross multiplying and dividing ratios is because it gives you the exact same answer if you are finding it per one, as I am here with per one minute. You can do it this way, it just wastes a bit of time.)

6 0

3 years ago

How many solutions can have two intersecting lines have? A. 3 B. 0 C. 1

Vladimir [108]

two intersecting lines can only have 1 solution.

4 0

3 years ago

Read 2 more answers

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, $b$ must be a natural number, which means that:

$1 + 2\cdot a\cdot c \ge 4$

$2\cdot a \cdot c \ge 3$

$a\cdot c \ge \frac{3}{2}$

But the lowest possible product made by two prime numbers is $2^{2} = 4$ . Hence, $a\cdot c \ge 4$ .

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Example: $a = 2$ , $c = 2$

$b = \sqrt{1 + 2\cdot (2)\cdot (2)}$

$b = 3$

4 0

3 years ago

WXYZ is congruent to PQRS. Find each measure of angle P

REY [17]

P=45

How do I Know that?

I added 35+100 and that equal to 180, so Then I subtracted 180-135 and that gave me 45. So P=35. Add all of them up to see if it = 180 and if it does, then your answer is correct. remeber 3 angles of a triangle =180.

3 0

3 years ago