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3 years ago

Write the following comparison as a ratio reduced to lowest terms.

Mathematics

2 answers:

olasank [31]3 years ago

6 0

Answer:

2.5 : 2

Step-by-step explanation:

Triss [41]3 years ago

5 0

Answer:

$2 : $5

Step-by-step explanation:

40 nickels = $2

50 dimes = $5

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an assembly line worker at Rob's Bicycle factory adds a seat to a bicycle at the rate of 2 seats in 11 minutes. Write a proporti

LuckyWell [14K]

Rate = 2 seats/11 minutes = 2/11 seats/min

Therefore the time required for s seats is
$(m \, min) = \frac{s \, seats}{ \frac{2}{11} \, \frac{seats}{min} } = \frac{11s}{2} \, min$
That is,
m = (11s)/2 min

When s = 16, obtain
$m = \frac{11(16)}{2} = 88 \, min$

When s = 19, obtain
$m = \frac{11(19)}{2} = 104.5 \, min$

Answers:
$m = \frac{11s}{2}$
When s = 16, m = 88 min
When s = 19, m = 104.5 min

3 0

3 years ago

Shankar has decided to train to be a Carbucks Barrista. Being young and inexperienced, for every order he makes a mistake in mak

astra-53 [7]

Answer:

Step-by-step explanation:

Since each trial is independent of the other

no of mistakes he does is binomial with p = 1/3

a) the probability that he makes no mistakes on his first 10 orders but the 11th order is a mistake

= $(\frac{2}{3}) ^{10} *\frac{1}{3}\\=\frac{2^{10} }{3^{11} }$

b) Prob that shanker quits = P(Shankar does I one mistake and Fran does not do the first one)+Prob (Shanker does mistake in the II one while Fran does both right)

= $\frac{1*5}{3*6} +\frac{2}{3} \frac{1}{3}(\frac{5}{6})^2 =\frac{5}{18} +\frac{50}{216} \\=\frac{55}{108}$

6 0

3 years ago

Prove that 1/sec0-tan0= sec0+tan0

Leviafan [203]

Answer:

Step-by-step explanation:

$\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}$

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2 years ago

Solving systems of equations<br><br> X-2y=0<br> Y=2x-3

bearhunter [10]

$\left \{ {{x-2y=0} \atop {y=2x-3}} \right. \\\\Substitute\ second\ equation\ to\ first:\\\\x-2(2x-3)=0\\x-4x+6=0\\-3x=-6\ \ \ \ \ |:-3\\x=2\\\\y=2\cdot2-3\\y=4-3=1\\\\ \left \{ {{y=1} \atop {x=2}} \right.$

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3 years ago

Read 2 more answers

Can you answer this, please?

sukhopar [10]

Answer:

it is irrational,because the product of an irrational number and a non zero rational number is irrational

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3 years ago