Answer:
A. yes
Step-by-step explanation:
The maximum height of the projectile is the maximum point that can be gotten from the projectile equation
The projectile reaches the maximum height after 5 seconds
The function is given as:

Differentiate the function with respect to t

Set to 0

So, we have:

Collect like terms


Solve for t


Hence, the projectile reaches the maximum after 5 seconds
Read more about maximum values at:
brainly.com/question/6636648
Answer:
9
Step-by-step explanation:
a²+b
Substituting values,
=> (-2)^2+5
=> 4 + 5
=> 9
Answer:
should be correct!
Step-by-step explanation: