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grandymaker [24]
2 years ago
10

Percy said that any real number for k would cause the system of equations to have no solution. Explain the error in Percy’s stat

ement.
6x + 4y = 14,

3x + 2y = k
Mathematics
2 answers:
MatroZZZ [7]2 years ago
5 0

Answer:

Except k=7, any real number for k would cause the system of equations to have no solution.

Step-by-step explanation:

In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.

Just for information, if k=7 the system will have infinitely many solutions.

Travka [436]2 years ago
5 0

Sample Response: k = 7 proves the equations are equivalent and, therefore, have infinitely many solutions. That is illustrated by the fact that multiplying 2 by 3x +2y = 7 will create the equivalent of 6x + 4y =14.

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zysi [14]

Answer:

11) mean=2   12) median=2   13)range =4  

Step-by-step explanation:

11) the set is

0,0,1,1,1,2,2,2,2,2,3,3,3,4,4

so add all these which will give you 30 and then divide that by how many numbers are there in the set which there are 15, so 30 divided 15 =2

12) arrange numbers from smallest to largest and the number exactly in the middle is the median

13)biggest number-smallest number

3 0
2 years ago
The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44
melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
2 years ago
I need help I’ll give u brainliest but i need an explanation or I can’t give it
slamgirl [31]

Answer:

the answer is a

Step-by-step explanation:

6 0
3 years ago
Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of
Kruka [31]

Answer:

Lola was in lead for \frac{6}{25} of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}

\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}

\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}

\text{Fraction for which Lola was in lead}=\frac{6}{25}

Therefore, Lola was in lead for \frac{6}{25} of a mile.

7 0
3 years ago
1. Round off each of the following to the nearest whole number.
Anni [7]

<em>☽------------❀-------------☾</em>

<em>Hi there!</em>

<em>~</em>

<em></em>8.71 = 9<em></em>

<em></em>26.01 = 26<em></em>

<em></em>69.48 = 69<em></em>

<em></em>103.72 = 104\\49.84 = 50\\101.35 = 101\\39.814 = 40\\1.23 = 1<em></em>

<em>❀Hope this helped you!❀</em>

<em>☽------------❀-------------☾</em>

<em></em>

4 0
2 years ago
Read 2 more answers
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