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3 years ago

Uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Mathematics

2 answers:

Dovator [93]3 years ago

5 0

Answer:

hiiiiiiiiiiiiiiiiiiiiiiiiiiihhhhhhhhhrrrrrrrrruuuuuuu

Solnce55 [7]3 years ago

5 0

Lolllllllllllllllllllllllllllllll thanks for freebies

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Write an equation (7,-4) and has a slope of m =-6

Ann [662]

Answer:

Step-by-step explanation:

y + 4 = -6(x - 7)

y + 4 = -6x + 42

y = -6x + 38

4 0

3 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

If ∆BCD ~ ∆GEF, find the value of x.

Karolina [17]

X=48
Y=44
Because the triangles are congruent.

8 0

3 years ago

Read 2 more answers

50 POINTS PLS HELP!!!

Viefleur [7K]

Answer:

1.) 90 ways

2.) 15,600 ways

3.) 24 ways

Step-by-step explanation:

1.) Let's say we are given 2 digits not equal to each other...The number of different orderings would be 2*1 = 2, or if we wanted the number of ways to order 2 digits chosen : 10*9 = 90 ways

2.) The number of ways to arrange 3 letters from 26 letters is:

26 Permutes 3 = 26! / (26 -3)! = 26*25*24 = 15,600 ways to choose 3 letters in a certain order

3.) 4 different chores. The number of ways to do them = 4*3*2 *1 = 24 ways

7 0

3 years ago

What is the additive inverse of 7/2 ?<br> A) −2/7<br> B) −7/2<br> C) 2/7<br> D) 7/2

snow_lady [41]

The additive inverse of 7/2 would be -7/2 (option B) Since its. opposite !

A)is the additive inverse of C) ; C) is the additive inverse of A) (not your answer)

B. is the additive inverse for this problem (7/2) so thats how we found that this is your answer (answer)

D is the same thing for the problem (7/2) (not your answer)

7/2 isnt the additive inverse for 7/2 because they are the SAME not the opposite.

+ = - (Positive = negative)

- = + (negative = positive)

6 0

3 years ago