(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
Answer:
Step-by-step explanation:
Use the Pythagorean Theorem to find the zeros of 6x² - 9x - 6.
x = [9±√(9²-4(6)(-6))]/[2(6)] = [9±√225]/12 = [9±15]/12 = 2, -½
Answer:
less than
Step-by-step explanation:
Think about it as if it was on the number line. What ever is further to the right is greater. This make 0.2 less that 0.4.
Answer:
9.21954445729
Step-by-step explanation:
A^2 + B^2 = C^2
7^2 = 6^2 = 85
The square root of 85 is...
9.21954445729
Answer:
2/3x-6
Step-by-step explanation:
