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3 years ago

PLEASE HELP ME !!!!!!!!!

Mathematics

1 answer:

Alex777 [14]3 years ago

3 0

Answer:

There are 2 contractions al and del. Name the parts of a verb Ar, Er, ir

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What are the common factors of 50 30 and 100

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10 is a common factor of 50 30 and 100. So is 2

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Stuart wants to find the value of 3 - 2

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To subtract fractions, we usually first find a common denominator.

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3 years ago

Math 170

Alinara [238K]

The given sides are 12 cm, 15 cm and 21 cm

Shortest side is 12 cm

As given that in real the shortest side is 200 m

So 12 cm=200 m

then 1 cm = $\frac{200}{12}=\frac{50}{3}$

Hence 15 cm = $\frac{50}{3} * 15 = 250$ m

21 cm = $\frac{50}{3} * 21 = 350$ m

So,,

15 cm in the photograph is 250 m long .

21 cm in the photograph is 350 long.

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3 years ago

A florist has 492 flowers. How many full bouquets of 12 flowers can he make?

Talja [164]

492 divided by 41= 41. He can make 41 full bouquets.

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3 years ago

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Recent homebuyers from a local developer allege that 30% of the houses this developer constructs have some major defect that wil

umka21 [38]

Answer:

3.54% probability of observing at most two defective homes out of a random sample of 20

Step-by-step explanation:

For each house that this developer constructs, there are only two possible outcomes. Either there are some major defect that will require substantial repairs, or there is not. The probability of a house having some major defect that will require substantial repairs is independent of other houses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

30% of the houses this developer constructs have some major defect that will require substantial repairs.

This means that $p = 0.3$

If the allegation is correct, what is the probability of observing at most two defective homes out of a random sample of 20

This is $P(X \leq 2)$ when n = 20. So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.3)^{0}.(0.7)^{20} = 0.0008$

$P(X = 1) = C_{20,1}.(0.3)^{1}.(0.7)^{19} = 0.0068$

$P(X = 2) = C_{20,2}.(0.3)^{2}.(0.7)^{18} = 0.0278$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0008 + 0.0068 + 0.0278 = 0.0354$

3.54% probability of observing at most two defective homes out of a random sample of 20

5 0

3 years ago