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3 years ago

What are the common factors of 50 30 and 100

Mathematics

2 answers:

Jlenok [28]3 years ago

7 0

The common factors are 1,5,and 10

Wittaler [7]3 years ago

6 0

10 is a common factor of 50 30 and 100. So is 2

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How do i find the altitudes of these points? (8,10), (5,-10), (0,0)

Naya [18.7K]

The first values are the x axis, wich are sideways but the second values are y axis wich are up and down so since you havent given much context they are 10 -10 and 0

6 0

3 years ago

The weight of male american between the ages 18 to 25 is normally distributed, with mean of 162.7 lb and a standard deviation of

MArishka [77]

Answer:

218.7 lb.

Step-by-step explanation:

We have been given that the weight of male american between the ages 18 to 25 is normally distributed, with mean of 162.7 lb and a standard deviation of 28 lb.

One definition of obesity states that a person is obese if the z-score of his or her weight is greater than 2.

We will use z-score formula to solve our given problem.

$z=\frac{x-\mu}{\sigma}$ , where,

$z=\text{ z-score}$ ,

$x=\text{ Random sample-score}$ ,

$\mu=\text{ Mean}$ ,

$\sigma=\text{ Standard deviation}$ .

Upon substituting our given values in z-score formula we will get,

$2=\frac{x-162.7}{28}$

Now let us solve for x.

Upon multiplying both sides of our equation by 28 we will get,

$2*28=\frac{x-162.7}{28}*28$

$56=x-162.7$

Let us add 162.7 to both sides of our equation.

$56+162.7=x-162.7+162.7$

$218.7=x$

Therefore, the obesity threshold weight for a young adult American male is 218.7 pounds.

6 0

3 years ago

Read 2 more answers

Which of the functions graphed below could be defined by a cubic equation?

alisha [4.7K]

Answer:

The first graph.

Step-by-step explanation:

I can see 3 graphs. The first one is a cubic equation.

3 0

4 years ago

If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? sin Θ = square root 2 ov

densk [106]

Answer:

$\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}$

Step-by-step explanation:

We have:

$\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}$

For sine use:

$\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x$

Substitute:

$\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}$