Answer:
(f o g)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x²-5
(f o g)(4)=?
(f o g)(4) = f(g(4))
Calculating g(4):
x=4→g(4)=4²-5
g(4)=16-5
g(4)=11
Replacing g(4)=11
(f o g)(4) = f(g(4))
(f o g)(4) = f(11)
Calculating f(11)
x=11→f(11)=4(11)+1
f(11)=44+1
f(11)=45
Replacing f(11)=45:
(f o g)(4) = f(11)
(f o g)(4) = 45
A. so the entire length of the to would be 25. You know 9 of those feet are not rope so you would subtract that from 25
25-9=16
16 would be the all the rope on top and you only want one side, so you would divide it by 2. The top right piece of rope would be 8ft long
Part b is the picture
Inequalities will have a <, >, <=, =>, = or will be worded as "Less than", "greater than", etc.
Equations must have mathematical functions and equal sign.
15=3x is an equation since 3x = 3*x
Finally, expressions are mathematical functions that have no equal signs.
Answer:
11 ounces
Step-by-step explanation:
- Find out how many ounces are in 4 pounds 2 ounces. There are 16 ounces in a pound, so that would be 66 ounces.
- Divide 66 by 6.
Hmm, the 2nd derivitve is good for finding concavity
let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient
so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x
so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points
f'(-1)>0
f'(1.5)<0
f'(3)>0
so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)
we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense
local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
