Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.
2 is the degree of the respective polynomial
The coding of the statistic is used to make it easier to work with the large sunshine data set
- The mean of the sunshine is 3.05

- The standard deviation is approximately <u>18.184</u>
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Reason:
The given parameters are;
The sample size, n = 3.
∑x = 947
Sample corrected sum of squares, Sₓₓ = 33,065.37
The mean and standard deviation = Required
Solution:

The mean of the daily total sunshine is therefore;



- The mean ≈ 3.05

Alternatively
,
The mean of the daily total sunshine,
≈3.05

Therefore;

Therefore;
The standard deviation,
≈ <u>18.184</u>
Learn more about coding of statistic data here:
brainly.com/question/14837870
First add 13.2 to both sides to get 0.5x > 0.1x + 33.2.
Then subtract 0.1x from both sides to get 0.4x > 33.2.
Lastly, divide each side by 0.4 to get a final answer of x > 83.
Hope this helps!