Write the missing number under each tick mark on the number line.

Helppppp pleaseeeee im giving 15 for this ;^;

Ivan

I’m pretty sure it should be ,B

5 0

3 years ago

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Make a figure that contains three triangles a parallelogram and a trapezoid using seven congruent line segment

Lubov Fominskaja [6]

We can't necessarily draw it out for you unless someone links something.

3 0

3 years ago

A geologist has collected 5 specimens of basaltic rock and 7 specimens of granite. The geologist instructs a laboratory assistan

MaRussiya [10]

The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:

$E(X) = 5.25, Var(X) = 0.5966$
P(X < 6) = 0.9545
P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The mean and the variance are:

$\mu = \frac{nk}{N}$

$\sigma^2 = \frac{nk(N-k)(N-n)}{N^2(N-1)}$

We have that:

5 + 7 = 12 rocks, which means that $N = 12$

9 are chosen, which means that $n = 9$

7 are granite, which means that $k = 7$

Question a:

$E(X) = \mu = \frac{9\times7}{12} = 5.25$

$Var(X) = \sigma^2 = \frac{9\times7(12-7)(12-9)}{12^2(12-1)} = 0.5966$

Thus:

$E(X) = 5.25, Var(X) = 0.5966$

Question b:

Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 4) = h(4,12,9,7) = \frac{C_{7,4}*C_{5,5}}{C_{12,9}} = 0.1591$

$P(X = 5) = h(5,12,9,7) = \frac{C_{7,5}*C_{5,4}}{C_{12,9}} = 0.4773$

$P(X = 6) = h(6,12,9,7) = \frac{C_{7,6}*C_{5,3}}{C_{12,9}} = 0.3181$

Thus

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1591 + 0.4773 + 0.3181 = 0.9545$

So P(X < 6) = 0.9545.

Question c:

5 of basaltic and 4 of granite: 0.1591 probability.

7 of granite is P(X = 7), in which

$P(X = 7) = h(7,12,9,7) = \frac{C_{7,7}*C_{5,2}}{C_{12,9}} = 0.0455$

0.1591 + 0.0455 = 0.2046, thus:

P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

A similar question is found at brainly.com/question/24008577

5 0

3 years ago

There is something wrong with the reason. I don’t know what it is. Could someone help me. The picture of the figure is on the ne

stira [4]

9514 1404 393

Answer:

CPCTC

Step-by-step explanation:

The applicable reason for statement 4 is "Corresponding Parts of Congruent Triangles are Congruent (CPCTC)".

The reason shown in your problem statement is applicable only within one triangle. The segments of interest are in two different triangles.

8 0

3 years ago

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Zara has forgotten her 4-digit PIN code. She knows the first digit is a prime number and the 4 digits make a number divisible by

vredina [299]

Answer:

2,500 different sets

Step-by-step explanation:

According to the scenario, calculation of the given data are as follows,

Let 4-digit PIN code be WXYZ

As first digit is a prime number

So, W = 1, 2, 3, 5, 7

n(W) = 5

X and Y are number from 0 - 9

So, n(X) = 10 & n(Y) = 10

Z makes the whole number divisible by 2.

So, Z must even number

So, Z = 0,2,4,6,8 or n(Z) = 5

We can calculate the number of different sets by using following formula,

n(W) × n(X) × n(Y) × n(Z)

By putting the value, we get

5 × 10 × 10 × 5 = 2,500

6 0

3 years ago