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postnew [5]
3 years ago
7

Which angle is vertically opposite to <CFD​

Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer:

show more of the pict i can't tell what it is

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Katrina drinks 0.5 gallons of water per day. Which expression shows how to find the number of cups of water she drinks in a week
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The answer is 128 i hope that helps
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If line segments A and B are parallel, which of the following pairs of angles are not equal?
anyanavicka [17]

Answer:

C: ∠6 and ∠2

Step-by-step explanation:

Step 1:

∠6 = ∠9        S.S. Int. ∠'s      (Same Side Interior ∠'s)

Step 2:

∠9 + ∠2 = 180°        Sum of line

Step 3:

∠9 ≠ ∠2

Answer:

C: ∠6 and ∠2

Hope This Helps :)

4 0
3 years ago
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What does x = ? 1 ÷ 11/2 = x
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Answer:

x = 2/11

Step-by-step explanation:

1 ÷ 11/2 = x

1 · 2/11 = x (Used the opposite reciprocal and changed to multiplication. This is the same as dividing with the original fraction.)

2/11 = x

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3 years ago
Which of the following are techniques used in geometric constructions with
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Answer= A
Explication
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The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va
Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore

4 0
3 years ago
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