Which angle is vertically opposite to <CFD
1 answer:
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We have that
<span>vertex (0,0)
and
focus (2.5, 0)
we know that
</span>vertex and focus lie on same vertical or horizontal line
<span>in this problem
</span>We can see that focus is right of vertex so parabola opens to right. It is horizontal parabola
<span>the equation is of the form
(y-k)</span>²=4a(x-h)
<span>where (h,k)-----> is the vertex
and
a------> </span>distance between vertex and focus
<span>
step 1
vertex (h,k)-------> (0,0)
step 2
find the distance a between point (0,0) and (2.5, 0)
a=</span>√[(0-0)²+(2.5-0)²]------> a=√(2.5)²------> a=2.5 units
<span>
the equation is
</span>(y-k)²=4a(x-h)------> (y-0)²=4*2.5*(x-0)-------> y²=10x
<span>
the answer is
</span> y²=10x
<span>
see the attached figure
</span>
<span>vertex (0,0)
and
focus (2.5, 0)
we know that
</span>vertex and focus lie on same vertical or horizontal line
<span>in this problem
</span>We can see that focus is right of vertex so parabola opens to right. It is horizontal parabola
<span>the equation is of the form
(y-k)</span>²=4a(x-h)
<span>where (h,k)-----> is the vertex
and
a------> </span>distance between vertex and focus
<span>
step 1
vertex (h,k)-------> (0,0)
step 2
find the distance a between point (0,0) and (2.5, 0)
a=</span>√[(0-0)²+(2.5-0)²]------> a=√(2.5)²------> a=2.5 units
<span>
the equation is
</span>(y-k)²=4a(x-h)------> (y-0)²=4*2.5*(x-0)-------> y²=10x
<span>
the answer is
</span> y²=10x
<span>
see the attached figure
</span>
Question:
The velocity function, in feet per second, is given for a particle moving along a straight line.
Find the displacement
Answer:
The displacement is 42.17ft
Step-by-step explanation:
Given
The displacement x, is calculated using:
Integrate
Substitute 12 and 1 for t respectively