All categories

3 years ago

What does x = ? 1 ÷ 11/2 = x

Mathematics

1 answer:

Yanka [14]3 years ago

7 0

Answer:

x = 2/11

Step-by-step explanation:

1 ÷ 11/2 = x

1 · 2/11 = x (Used the opposite reciprocal and changed to multiplication. This is the same as dividing with the original fraction.)

2/11 = x

You might be interested in

If 40% of x + 20% of x + 1/10 = 75% of x, then find the value of x. Please give answers with steps

tatyana61 [14]

Answer:

x = 13/12

Step-by-step explanation:

explain on image

3 0

3 years ago

Read 2 more answers

Pls help!!! thank you in advance

Oliga [24]

answer simple

i thinks its b

5 0

3 years ago

Read 2 more answers

What is the derivative of the function below?

11111nata11111 [884]

$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$

8 0

3 years ago

Examine the right triangle. A right triangle with side lengths 17 centimeters and 48 centimeters. The hypotenuse is unknown. Wha

Dimas [21]

Answer:

The answer to your question is c = $\sqrt{2593}$

Step-by-step explanation:

Data

right triangle

short leg = 17 cm

long leg = 48 cm

hypotenuse = ?

Process

-Use the Pythagorean theorem to find the answer

c² = a² + b²

c = hypotenuse

a = short leg = 17 cm

b = long leg = 48 cm

- Substitution

c² = 17² + 48²

-Simplification

c² = 289 + 2304

c² = 2593

-Result

c = $\sqrt{2593}$

5 0

3 years ago

Read 2 more answers

What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27

malfutka [58]

Answer with explanation:

$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0

3 years ago

Read 2 more answers