Step-by-step explanation:
Vamos simplificar passo a passo.
k2-6k4-(3k4+k2+2)
Distribua o sinal negativo:
=k2-6k4+-1(3k4+k2+2)
=k2+-6k4+-1(3k4)+-1k2+(-1)(2)
=k2+-6k4+-3k4+-k2+-2
Combine os termos semelhantes:
=k2+-6k4+-3k4+-k2+-2
=(-6k4+-3k4)+(k2+-k2)+(-2)
=-9k4+-2
Responda:
=-9k4-2
4 minutes 34 seconds will takes to empty the tank, if the starts completely full and oil drained at a rate of 2.5
per minute.
Step-by-step explanation:
The given is,
Tank is shaped like a cylinder that is 3 ft long with a diameter of 2.2 ft.
Oil drained at a rate of 2.5
per minute.
Step:1
Time taken to dry the oil tank is,
T =
....................................(1)
Step:2
Volume of the oil is,
.................................................(2)
Where, r - Radius of Cylinder

r = 1.1 ft
From eqn (1),
V =
×
× 3
= 11.40398 
Step:3
From equation (1)
=
= 4.56
= 4.56 minutes
T = 4 minutes 34 seconds
Result:
Time taken to dry the oil tank is 4 minutes 34 seconds, if a cylinder is 3 ft long with a diameter of 2.2 ft and oil is drained at a rate of 2.5ft^3 per minute.
So basically your doing unit rates? Well guess what, I'm studying about that also, and I have a little understanding about unit rates, have you done ratios before?