Answer:
x = 2 and y = 7
Step-by-step explanation:
The given equations are :
Squaring both sides of equation (2)
Put the value of y from equation (2)
Put the value of x in equation (2)
y-x = 5
y = 5+x
= 5+2
= 7
Hence, the solution of the given equations are (2,7).
Answer:
Step-by-step explanation:
Given that
f(-2) = 1 and f(2) = 1
The question is here we have values for -1 and 1 the same and hence we must get a c such that f(c) =0
Because we are not getting here c value does it violate the intermedate value theorem
Please go through the conditions for intermediate theorem to be valid
If f(x) is continuous in the interval [a,b] and f is differentiable in the interval (a,b) and if f(b) = f(a) then we have a c in the interval (a,b) such that f(c) = 0
But our f(x) is not differntiable in the interval (-2,2) because at x =0 we get left derivative =-1 and right derivative =1
So f is not differntiable in the interval.
Hence intermediate theorem cannot be applied here.