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tankabanditka [31]
1 year ago
12

8. Patrice and Don buy a home for $92,000. The property tax rate is$39.50 per $1,000 of assessed value. The assessment rate is 4

1%.How much is their property tax?9. Find Patrice and Don's effective tax rate. Use the informationin problem 8.
Mathematics
1 answer:
Kaylis [27]1 year ago
3 0

We start by calculating the assessed value, that is 41% of the price.

The price is $92,000.

Then, the assessed value is:

AV=a\cdot P=\frac{41}{100}\cdot92000=0.41\cdot92000=37720

The property tax rate is $39.50 per $1000 of assessed value, so we can express this rate as:

\text{tax rate}=\frac{39.50}{1000}=0.0395

We then can multiply this rate by the assessed value to calculate the total property tax:

\text{tax}=0.0395\cdot37720=1489.94

NOTE: we could have also multiplied 39.50 by 37.72. The value 37.72 is the thousands of dollars of assessed value. We would have obtained the same result: 39.50*37.72=1489.94.

Answer: the property tax is $1,489.94.

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3 c ock

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Reason being of you add 1 c ock and 2 c ock you get 3 c ock

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Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

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\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

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3 0
3 years ago
In the past, 21% of all homes with a stay-at-home parent, the father is the stay-at-home parent. An independent research firm ha
Afina-wow [57]

Answer:

A sample size of 79 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = 0.21

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.  

What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?

A sample size of n is needed.

n is found when M = 0.09. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.21*0.79}{n}}

0.09\sqrt{n} = 1.96\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.96\sqrt{0.21*0.79}}{0.09}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.21*0.79}}{0.09})^{2}

n = 78.68

Rounding up to the nearest whole number.

A sample size of 79 is needed.

4 0
3 years ago
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photoshop1234 [79]

Answer: 19 units

Step-by-step explanation:

Count from A down then the left until you reach B.

8 0
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